Step-by-step explanation:
In this case we have:
Δx = 3/n
b − a = 3
a = 1
b = 4
So the integral is:
∫₁⁴ √x dx
To evaluate the integral, we write the radical as an exponent.
∫₁⁴ x^½ dx
= ⅔ x^³/₂ + C |₁⁴
= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)
= ⅔ (8) + C − ⅔ − C
= 14/3
If ∫₁⁴ f(x) dx = e⁴ − e, then:
∫₁⁴ (2f(x) − 1) dx
= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx
= 2 (e⁴ − e) − (x + C) |₁⁴
= 2e⁴ − 2e − 3
∫ sec²(x/k) dx
k ∫ 1/k sec²(x/k) dx
k tan(x/k) + C
Evaluating between x=0 and x=π/2:
k tan(π/(2k)) + C − (k tan(0) + C)
k tan(π/(2k))
Setting this equal to k:
k tan(π/(2k)) = k
tan(π/(2k)) = 1
π/(2k) = π/4
1/(2k) = 1/4
2k = 4
k = 2
You would want to add all of the angles together to find the sum. Set this equal to 360.
2x-9 + 2x-9 + x + x + x = 360
Combine like terms,
7x-18 = 360
Add 18 to both sides,
7x = 378
Divvied both sides by 7,
x = 54
Answer: y=4,728,779,608,739,020,800
Step-by-step explanation: based on the values you have for m & b it would be...
y=4,200 x 
y=4,200 x 1,125,899,906,842,624
y=4,728,779,608,739,020,800
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player 
.
Now we know that;
Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
Since the track is 1/3 kilometre all you have to do is multiply 1/3 x 4!
When you do that you get that the runner would travel 4/3 kilometre or 1 & 1/3 kilometre of the track.
