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3 years ago

To rent a certain meeting room, a college charges a reservation fee of $33

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

3 0

Answer:

The meeting room must be rented for less than 7 hours

Step-by-step explanation:

There are 2 types of costs in this situation

Fixed cost = $ 33

Variable cost = 9.70t

Where t is the number of hours.

The total cost C will be the sum of the fixed cost and the variable cost

$C = 33 + 9.70t$

We want C to be less than 100.90

So:

$33 + 9.70t$

We solve for t and obtain.

$9.70t$

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joey enter a hot dog eating competition. He ate 30 1/2 hot dogs in 3/4 minutes. How many hot dogs did he eat in one min.

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2 years ago

Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?

algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.

Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.

Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.

So, the coordinates of the endpoint are $T = (5,-13)$

If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.

We have $G = (-3, 5)$ and $T = (x_T,y_T)$ . The midpoint is computed as

$A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)$

So, you have the equations

$\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4$

Multply both equations by 2 to get

$-3+x_T = 2,\qquad 5+y_T = -8$

Move the constants to the right hand sides to get

$x_T = 5,\qquad y_T = -13$

8 0

3 years ago

The sum of the consecutive numbers is 111. What is the smallest of the three numbers?

sammy [17]

Let
x = first consecutive number
x + 1 = second consecutive number
x + 2 = third consecutive number

The sum of these numbers are 111.
x + x + 1 + x + 2 = 111
3x = 111 - 1 - 2
3x = 108
x = 36

Therefore, the smallest number is 36 because other numbers are 37 and 38.

8 0

3 years ago

Read 2 more answers

If sin theta = (4)/(7), theta in quadrant II, find the exact value of (a) cos theta (b) sin (theta + (pi) / (6) ) (c) cos (the

EleoNora [17]

Answer:

a) $\cos(\theta) = \frac{\sqrt[]{33}}{7}$

b) $\sin(\theta + \frac{\pi}{6})\frac{-3\sqrt[]{11}+4}{14}$

c) $\cos(\theta-\pi)=\frac{\sqrt[]{33}}{7}$

d) $\tan(\theta + \frac{\pi}{4}) = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}$

Step-by-step explanation:

We will use the following trigonometric identities

$\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\cos(\alpha)\sin(\beta)$

$\cos(\alpha+\beta) = \cos(\alpha)\cos(\beta)-\sin(\alpha)\sin(\beta)$ $\tan(\alpha+\beta) = \frac{\tan(\alpha)+\tan(\beta)}{1-\tan(\alpha)\tan(\beta)}$ .

Recall that given a right triangle, the sin(theta) is defined by opposite side/hypotenuse. Since we know that the angle is in quadrant 2, we know that x should be a negative number. We will use pythagoras theorem to find out the value of x. We have that

$x^2+4^2 = 7 ^2$

which implies that $x=-\sqrt[]{49-16} = -\sqrt[]{33}$ . Recall that cos(theta) is defined by adjacent side/hypotenuse. So, we know that the hypotenuse is 7, then

$\cos(\theta) = \frac{-\sqrt[]{33}}{7}$

b)Recall that $\sin(\frac{\pi}{6}) =\frac{1}{2} , \cos(\frac{\pi}{6}) = \frac{\sqrt[]{3}}{2}$ , then using the identity from above, we have that

$\sin(\theta + \frac{\pi}{6}) = \sin(\theta)\cos(\frac{\pi}{6})+\cos(\alpha)\sin(\frac{\pi}{6}) = \frac{4}{7}\frac{1}{2}-\frac{\sqrt[]{33}}{7}\frac{\sqrt[]{3}}{2} = \frac{-3\sqrt[]{11}+4}{14}$

c) Recall that $\sin(\pi)=0, \cos(\pi)=-1$ . Then,

$\cos(\theta-\pi)=\cos(\theta)\cos(\pi)+\sin(\theta)\sin(\pi) = \frac{-\sqrt[]{33}}{7}\cdot(-1) + 0 = \frac{\sqrt[]{33}}{7}$

d) Recall that $\tan(\frac{\pi}{4}) = 1$ and $\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}=\frac{-4}{\sqrt[]{33}}$ . Then

$\tan(\theta+\frac{\pi}{4}) = \frac{\tan(\theta)+\tan(\frac{\pi}{4})}{1-\tan(\theta)\tan(\frac{\pi}{4})} = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}$

5 0

3 years ago

3) Find the mode.

boyakko [2]

Answer:

Step-by-step explanation:

since there are two mode that means it is 6 and 8 and mode is how many time a number appears

8 0

3 years ago