I believe it would be 13p im not for sure though
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Answer: </h3><h3>
speed of train A = 44 mph</h3>
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Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph
10x^3(8x^3+3x)
([10x^3 x 8x^3]+ [10x^3 x 3x])
80x^6+ 30x^4
•this is as simplified as it gets; it isn’t possible to add or subtract numbers with different exponents.
please vote brainliest if it helped you and have a great day! :)
Answer:
All of the points lie on the graph except for the coordinates (-2,1) and (1,5)
Step-by-step explanation:
The answer would be X=1/2y
