Answer:
18 is the GCF
Step-by-step explanation:
Factors of 18: 1, 2, 3, 6, 9, 18
Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54
9/12 is number 1. and Number 2 is 1/2 =4/8 and that is 1/2
Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: ![{\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20P%28k%7B%5Ctext%7B%20events%20in%20interval%7D%7D%29%3D%7B%5Cfrac%20%7B%5Clambda%20%5E%7Bk%7De%5E%7B-%5Clambda%20%7D%7D%7Bk%21%7D%7D%7D)
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:
![P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}](https://tex.z-dn.net/?f=P%28k%20%3E%202%29%3D%201%20-%20%7BP%28k%20%3D%200%29%20%2B%20P%28k%20%3D%201%29%20%2B%20P%28k%20%3D%202%29%7D)
Substitute the respective values in the above formula.
![P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})](https://tex.z-dn.net/?f=P%28k%20%3E%202%29%3D%201%20-%20%28%7B%5Cfrac%20%7B2.9%20%5E%7B0%7De%5E%7B-2.9%7D%7D%7B0%21%7D%7D%20%2B%20%5Cfrac%20%7B2.9%20%5E%7B1%7De%5E%7B-2.9%7D%7D%7B1%21%7D%7D%20%2B%20%5Cfrac%20%7B2.9%20%5E%7B2%7De%5E%7B-2.9%7D%7D%7B2%21%7D%7D%29)
![P(k > 2)= 1 - (0.44596)](https://tex.z-dn.net/?f=P%28k%20%3E%202%29%3D%201%20-%20%280.44596%29)
![P(k > 2)=0.55404](https://tex.z-dn.net/?f=P%28k%20%3E%202%29%3D0.55404)
Hence, the required probability is 0.55404.
Answer
true
Step-by-step explanation:
Divide the total earnings for the workweek, including earnings during overtime hours,