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3 years ago

Please help and show all work!

Mathematics

1 answer:

Soloha48 [4]3 years ago

3 0

2 is Reflexive property
4 is (I don't remember the specific property of this)

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___,36 ,108 ,324 ,972

hjlf

12

First figure out of it is a arithmetic or geometric sequence, in this case it is a geometric sequence because you have to multiply, not add to find the next number.

Divide one number, I'll pick 324 by the number before it, 108, you get three.

Now divide 36 by 3, you get 12.

To check, multiply 12 by 3, you get 36, multiply that by 3, you get 108, and so on and so forth.

3 0

3 years ago

Solve for q. Write your answer as “q=___”

wolverine [178]

Answer:

7q-46= 3q +6

7q-3q = 6+ 46

4q= 52

4q/4= 52/4

q= 13

3 0

3 years ago

Read 2 more answers

Which function BEST expresses the linear relationship displayed by the scatter plot?

Harrizon [31]

Answer:

Step-by-step explanation:

We want a line of best fit, which means we want to create a line that the data points will lie closest to.

One thing we can do is find the slope between the bottom-leftmost point and the top-rightmost point. This is because if we were to draw a line connecting these two, it will cut through the data quite well.

Those two points are (9, 15) and (16, 18), so the slope is change in y divided by the change in x:

(18 - 15) ÷ (16 - 9) = 3 ÷ 7 ≈ 0.4

Eliminate A and B.

Now we need to determine the y-intercept. This needs no calculations; simply look at the graph: there's no way a line cutting through the y-intercept point of (0, 18) will perfectly match the data points; instead it must be a y-intercept lower than 18. So, eliminate D.

The answer is C.

6 0

3 years ago

Read 2 more answers

Assume y=x²+3x+6. what is the avg rate of change of y with respect to x as x changes from -4 to -2

AURORKA [14]

The average rate of change is 3

5 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

2 years ago