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Leona [35]
4 years ago
6

Solve |2x – 3| = 11. Show each step of your work.

Mathematics
1 answer:
Klio2033 [76]4 years ago
8 0

Answer:

x =7       or              x = -4

Step-by-step explanation:

|2x – 3| = 11

There are two solutions to an absolute value equation, one positive and one negative

2x-3 =11    or 2x-3 = -11

Add 3 to each side

2x-3+3 = 11 +3    2x-3+3 = -11+3

2x = 14                 2x = -8

Divide each side by 2

2x/2 =14/2           2x/2 = -8/2

x =7                     x = -4

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I believe the answer Is A.x/3y.
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What is the total amount that Mathews bank will receive after lending him 8000 for four years
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32,000

Step-by-step explanation:

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Lorraine is picking blackberries in her backyard at a rate of 15 berries per minute. After 16 minutes of picking, there are stil
lyudmila [28]

137 - 16X = Y

Since Lorraine is picking blackberries in her backyard at a rate of 15 berries per minute, and after 16 minutes of picking, there are still 137 blackberries left to pick, to determine an equation that models how many berries are left (y) after x minutes of picking, the following calculation must be performed:

137 - 16X = Y

Thus, for example, after 5 minutes the calculation would be as follows:

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8 0
2 years ago
what is the rate of change for the linear relationship modeled in the table? x y −1 10 1 9 3 8 5 7 -1/2 0 1/2 2
Vesnalui [34]

Answer:

Rate of change for the linear relationship modeled is \dfrac{-1}{2}

Step-by-step explanation:

As the there is a linear relationship in the points, so all these points will be on a single straight line. Hence the slope will be same throughout all the points.

We know that, the slope of the line joining (x₁, y₁) and (x₂, y₂) is,

m=\dfrac{y_2-y_1}{x_2-x_1}

Putting the points as (-1, 10) and (1, 9), we get

m=\dfrac{9-10}{1-(-1)}

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7 0
3 years ago
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NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

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For second box plot

\text{Minimum value }= 56

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Median=74

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First class has greater median.

second class has greater third quartile.

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Second class has greater inter quartile range.  It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

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