Question

What is the volume of the item described?

Answer 1

612 π ​ m³ and 1922 m³ are your answers.

Answer 2

Answer

612 π ​ m³

1922 m³

Explanation

The body of the rocket is a cylinder; to find its volume, we are going to use the formula for the volume of a cylinder:

$V=\pi r^2h$

where

$r$ is the radius of the cylinder

$h$ is the height

We know from our problem that the radius of the cylinder is 6 m and its height is 16 m, so let's replace the values:

$V=\pi (6m)^2(16m)$

$V=\pi (36m^2)(16m)$

$V=576\pi m^3$

$V=1809m^3$

The volume of the cylinder is $1810m^3$

To find the volume of the cone, we are going to use the formula:

$V=\pi r^2\frac{h}{3}$

where

$r$ is the radius

$h$ is the height

We know form our problem that the radius of the cone is 6 m and its height is 3 m, so let't replace the values:

$V=\pi (6m)^2(\frac{3m}{3} )$

$V=\pi (36m^2)(1m)$

$V=36\pi m^3$

$V=113m^3$

Now, we just need to add the volumes in terms of $\pi$ and the volumes rounded to the nearest whole:

Volume of the item in terms of π = $576\pi m^3+36\pi m^3=612\pi m^3$

Volume of the item rounded = $1809m^3+113m^3=1922m^3$