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Ratling [72]
3 years ago
9

HELP ASAP K THANKS BYE

Mathematics
2 answers:
lana [24]3 years ago
6 0

Answer:


the answer is x=4

Vika [28.1K]3 years ago
5 0

Answer:

x can be 4 so A

because the line under the greater sign it  means it can be the same

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A computer chip has the dimensions 8mm x 8mm but the scale is drawn with the ...
Yuliya22 [10]
Given that the chip has a dimension of 8 mm by 8 mm which can be written as 0.8 cm by 0.8 cm, is drawn to scale and the dimensions of the plot is 4 cm by 4 cm, the scale of the drawing will be:
0.8 cm is represented by 4 cm
thus;
4 cm rep 0.8 cm
1 cm rep 0.2 cm
The answer is:
1 cm rep 0.2 cm  
6 0
3 years ago
Solve this rational equation 5/z + 1/5 = 7/z
Murrr4er [49]

Answer:

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3 0
3 years ago
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What is ∛1728. Then multiplied by ∛14903
NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate \sqrt[3]{1728} and then multiply the result by \sqrt[3]{14903}

Let us first evaluate \sqrt[3]{1728}

\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12

As need to multiply 12 by \sqrt[3]{14903}

\Rightarrow 12 \times \sqrt[3]{14903}

On solving \sqrt[3]{14903}, we get

\sqrt[3]{14903}=24.608

\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0
3 years ago
Please help asap!!! DX DX DX
Gnoma [55]
I believe the answer is C becuz i had that same answer and question so I HOPED I HELPED AND SMASH THAT THANKS BUTTON AND ADD ME AS A FRIEND
8 0
3 years ago
Read 2 more answers
I need help on my math
shtirl [24]

Answer:

y = -5/4x - 4

Step-by-step explanation:

The equation they give you is in slope intercept form.  y=mx+b.  The m is the slope (-5/4).  Since they want a parallel line you keep the same slope for point slope form.  Point slope formula is y-y1=m(x-x1). the y1 and x1 are where you plug in the coordinates they give you.

y - 1 = -5/4x (x + 4)

y - 1 = -5/4x - 5

y = -5/4x - 4

4 0
3 years ago
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