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Ratling [72]
3 years ago
9

Simplify the radical expression by rationalizing the denominat o 3/11

Mathematics
2 answers:
Andru [333]3 years ago
6 0

Answer:

The answer is 3√11/11



8090 [49]3 years ago
5 0
Do you mean 3/√11 ? In this case, you'll have to multiply both, numerator and denominator by the denominator ... 
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3 acute angles with different measures and 1 right angle and 2 acute angles with same measures

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jane drove 50 miles more then her husband jim. the total distance traveled was 230 miles. find the number of miles that each of
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Find the quadratic function y=ax^2 + bx + c whose graph passes through the given points. ​(-3​,37​), ​(2​,-8​), ​(-1​,13)
melamori03 [73]

The quadratic function is y=1x^{2} + (-8)x + 4

Step-by-step explanation:

The quadratic function given is ax^{2} + bx + c=y

and same quadratic function is passes through (-3​,37​), ​(2​,-8​), ​(-1​,13)

Replacing points one by one

we get,

For (-3​,37​) :

a(-3)^{2} + b(-3) + c=37

9a + -3b + c=37 =<em> equation 1 </em>

For (2​,-8​) :

a(2)^{2} + b(2) + c=(-8)

4a + 2b + c=(-8) =  <em>equation 2</em>

For ​(-1​,13)

a(-1)^{2} + b(-1) + c=(13)

a + -1b + c=13 = <em>equation 3</em>

Solving the linear equation to get values of a,b,c

Subtract equation 2 with equation 3

we get,(4a + 2b + c)-(a + -1b + c)=(-8)-13

(3a + 3b )=(-21)

(a + b )=(-7)  = <em>equation 4</em>

Now, Subtract equation 1 with equation 2

we get,(9a + -3b + c)-(4a + 2b + c)=(37)-(-8)

(5a - 5b )=(45)

(a - b )=(9)  = <em>equation 5</em>

Now, Add equation 4 with equation 5

we get,(a + b)+(a - b)=(-7)+(9)

(2a - 0b )=(2)

(a)=1  

Replacing value of a in <em>equation 5</em>

(a - b )=(9)

(1 - b )=(9)

(b)=(-8)

Replacing value of a and b in <em>equation 1</em>

9a + -3b + c=37

9(1) + -3(-8) + c=37

9 + 24 + c=37

c=4

Thus,

The quadratic function y=1x^{2} + (-8)x + 4

3 0
3 years ago
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