Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
If Josefina is the coach of a baseball team, <span><span>she is not necessarily qualified to be any of these choices</span>.
the president of the country
the mayor of the city
the mother of two children
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Answer:
top left:1/5, 2/7, 3/5, 5/7, 31/35
top right:2/5, 2/3, 7/10, 4/5, 9/10
bottom left:9/8, 15/8, 13/6, 9/4, 15/6
bottom right:13/10, 13/6, 11/5, 25/6, 21/5
Step-by-step explanation:
C. 5 bc u jus gotta add it on the calculator