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2 years ago

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If the item regularly cost d dollars and is discounted 20 percent which of the following represents discount price dollar

1 answer:

Step2247 [10]2 years ago

5 0

It’s Definitely gotta be D. .80d

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PLZ I NEED THIS QUICK, I WILL GIVE BRAINLSET FOR THE FASTEST AND CORRECT ANSWER

patriot [66]

Answer:

$95

Step-by-step explanation:

you had to subtract the two numbers .

4 0

2 years ago

Read 2 more answers

(9/16)^−1/2 How do I solve this equation?

vlada-n [284]

$\left(\dfrac{9}{16}\right)^{-\tfrac{1}{2}}=\\
\left(\dfrac{16}{9}\right)^{\tfrac{1}{2}}=\\
\sqrt{\dfrac{16}{9}}=\\
\dfrac{4}{3}$

4 0

3 years ago

In an intro stats class, 57% percent of students eat breakfast in the morning and 80% of students floss their teeth. Forty-six p

WINSTONCH [101]

Answer: B. 11%

Step-by-step explanation:

Let A = Event that students eat breakfast in the morning.

B= Event that students floss their teeth.

We are given P(A)=57%=0.57

P(B)=80%=0.80

P(A∩B) = 46% =0.46

Now, the probability that a student from this class eats break feast but does not floss their teeth :-

$P(A-B)=P(A)-P(A\cap B)\\\\ = 0.57-0.46=0.11=11\%$

Hence, the probability that a student from this class eats break feast but does not floss their teeth= 11%

3 0

3 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

2 years ago

Alexxx [7]

Add all three expressions up and set them equal to 180 degrees, because there are 180 degrees in a triangle.

3 0

3 years ago