Question

If tan0 = 12/5 and cos0 = -5/13, then what is sin0

Answer 1

Question:

if tan$\theta$  = 12/5 and cos$\theta$  = -5/13, then what is sin$\theta$

Answer:

$sin \theta = \frac{ -12}{13}$

Step-by-step explanation:

Given:

tan$\theta$ = 12/5

cos$\theta$  = -5/13

To find:

sin$\theta$ = ?

Solution:

We can find the sin$\theta$ value by using the tan ratio and cosine ratio

$cos = \frac{ adjacent }{hypotenuse} = \frac{ -5}{13}$

$sin = \frac{ opposite}{hypotenuse}$

$sin \theta = tan \theta \times cos\theta$

$sin \theta = \frac{opposite}{adjacent} \times \frac{adjacent}{hypotenuse}$ =  $\frac{ opposite}{hypotenuse}$

On substituting the values,

$sin \theta = \frac{ 12}{5} \times \frac{-5}{13}$

$sin \theta = \frac{ -12}{13}$