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Blababa [14]
3 years ago
14

A dog weighs two pounds less than three times the weight of a cat. The dog also weights twenty-two more pounds than the cat. Wri

te and solve an equation to find the weights of the cat and the dog.
Mathematics
1 answer:
8090 [49]3 years ago
4 0

Answer:

Weight of dog: 34 pounds,

Weight of cat: 12 pounds.

Step-by-step explanation:

Let d represent weight of dog and c represent weight of cat.

We have been given that a dog weighs two pounds less than three times the weight of a cat.

3 times weight of cat: 3c

We can represent the given information in an equation as:

d=3c-2...(1)

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

d=c+22...(2)

Equate both equations:

3c-2=c+22

3c-c-2=c-c+22

2c-2=22

2c-2+2=22+2

2c=24

\frac{2c}{2}=\frac{24}{2}

c=12

Therefore, the weight of cat is 12 pounds.

Substitute c=12 in equation (2)

d=c+22

d=12+22

d=34

Therefore, the weight of dog is 34 pounds.

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Dima020 [189]

Answer:

Option (1), (2) , (7) and (8) is correct.

Step-by-step explanation:

Given: a║b  and d and c be transversal , We have to find the value of x and measure of angle 1 and 2.

Since, a║b  and d be a transversal  then ,

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Thus, m∠2 = 58°

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Since, a║b  and c be a transversal  then,

  ∠XYZ = ∠QZU = (4X-10)°  (Corresponding angles)

Thus, m∠1 =  (4X-10)°

Also, Since, 'a' is a straight line.

Sum of angles on a straight line is 180°.

⇒ ∠PZA + ∠PZQ + ∠QZU = 180°

⇒ 58° +(3X-1)°+(4X-10)° = 180°

⇒ 58° + 7x - 11 = 180°

⇒ 47° + 7x  = 180°

⇒  7x  = 180°- 47°

⇒  7x  = 133°

⇒  x  = 19°

Put x = 19 in (3X-1)° and (4X-10)° , we get

(3X-1)° = (3(19)-1)° = 56°

(4X-10)° = (4(19)-10)°= 66

Thus, (3X-1)° ≠ (4X-10)°

Thus, option (1), (2) , (7) and (8) is correct.


5 0
3 years ago
Read 2 more answers
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Anni [7]

Answer:

12.42 = 1242 / 100;

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Step-by-step explanation:


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Step-by-step explanation:

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bija089 [108]

Answer:

4 pounds with a membership

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Step-by-step explanation:

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