2 years ago

Given that 4^-n=32 Find the value of n

Mathematics

1 answer:

ch4aika [34]2 years ago

8 0

Step-by-step explanation:

${4}^{ - n} = 32$

${2}^{ -2 n} = {2}^{5}$

$- 2n = 5$

$n = \frac{ - 5}{2}$

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