Given that 4^-n=32 Find the value of n

Mathematics

1 answer:

ch4aika [34]3 years ago

8 0

Step-by-step explanation:

${4}^{ - n} = 32$

${2}^{ -2 n} = {2}^{5}$

$- 2n = 5$

$n = \frac{ - 5}{2}$

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3 years ago

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Yuri [45]

Hey there!

$3x^2 + x -5 = 0$

This equation is in standard form, which is $ax^2+bx+c=0$ .

We are going to solve this with the quadratic equation, so we need to find the values for a, b, and c in the given equation. We can just look at it and identify the variables.

a = 3, b = 1, c = -5

Let's plug these values into the quadratic equation:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

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$x=\frac{-1\pm\sqrt{1+60} }{6}$

Add 1 and 60.

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This is our answer in exact form. If you need this as an approximate value, let me know and I will do that for you.

Hope this helps!

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3 years ago

Please help me do not and please give me an explanation too please. No link please

krok68 [10]

Answer:

I'm pretty sure it's D.40 because it's the biggest number and 6+13+17 is only a bit bigger than 24. Also, all the numbers add up to 60 and 27 is only a bit less than 50% of 60

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3 years ago

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Jobisdone [24]

Answer:

The answer is