1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maria [59]
2 years ago
11

for one roll of die, let a be the event "even" and let b be the event "4,6" find the probability p(a)

Mathematics
1 answer:
Llana [10]2 years ago
5 0

Answer:

gltt bow

Step-by-step explanation:

got it right on edg

You might be interested in
Please help me quick please solve in inequality form
katovenus [111]

Answer:

D

Step-by-step explanation:

3 0
2 years ago
Comparing decimals 0.49 to 0.94 is that equal ? or 0.94 more..?​
ddd [48]

the simple fact that 94 is 49 backwards means nothing, anymore than say 001 and 100 are equal quantities or related other than in the digits.

so, 0.49 or 49/100 and 0.94 or 94/100, are two values, both are at the one hundredth level, so to see who is larger, we can nevermind the 100 and look at the numerator, 94 is clearly much larger than 49.

8 0
3 years ago
The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April,
Karolina [17]

Answer:

a)Null hypothesis:\mu = 24.57  

Alternative hypothesis:\mu \neq 24.57  

b) df=n-1=30-1=29  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(29)}  

c)  If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 24.57 at 5% of signficance.

d)  For this case since we have a two tailed test we need to find two critical values and we need 0.025 of the area on each tail of the t distribution with 29 degrees of freedom. The critical values are given by:

t_{crit}=\pm 2.045

And the rejection zone would be given by:

(-\infty , -2.045) U(2.045,\infty)

Since pur calculated value is not on the rejection zone we Fail to reject the null hypothesis.

Step-by-step explanation:

The mean hourly wage for employees in goods-producing industries is currently $24.57. Suppose we take a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries.

a. State the null and alternative hypotheses we should use to test whether the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries.

We need to conduct a hypothesis in order to check if the mean is equal to 24.57 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 24.57  

Alternative hypothesis:\mu \neq 24.57  

b. Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population standard deviation of $2.40 per hour and compute the p-value.

\bar X=23.89 represent the sample mean  

s=2.4 represent the sample standard deviation

n=30 sample size  

\mu_o =24.57 represent the value that we want to test

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

If we analyze the size for the sample is = 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{23.89-24.57}{\frac{2.4}{\sqrt{30}}}=-1.552    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=30-1=29  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(29)}  

c. With  α = 0.05  as the level of significance, what is your conclusion?

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 24.57 at 5% of signficance.

d. Repeat the preceding hypothesis test using the critical value approach.

For this case since we have a two tailed test we need to find two critical values and we need 0.025 of the area on each tail of the t distribution with 29 degrees of freedom. The critical values are given by:

t_{crit}=\pm 2.045

And the rejection zone would be given by:

(-\infty , -2.045) U(2.045,\infty)

Since pur calculated value is not on the rejection zone we Fail to reject the null hypothesis.

4 0
2 years ago
May I know why is the answer 1/2? Any idea <br><br> Thank you!
ElenaW [278]

let's put value of t in equation.

x = 2√t

x = 2√y

x/2 = √y

(x/2)^2 = y

y = x^2 /4

now let's differentiate it with respect to x.

dy/dx = 2x/4 = x/2

differentiating again wrt to x

d^2y/dx^2 = 1/2

8 0
2 years ago
A manufacturing company with 450 employees begins a new product line and must increase their number of employees by 18%. How man
nika2105 [10]
The answer would <span>531. You would add 18% more employees to the company so the answer is 531. I really hope this helped you. Have a nice day!</span>
4 0
3 years ago
Other questions:
  • PLEASE HELP ASAPPPPPPPP
    10·1 answer
  • ome pleated draperies must be twice as wide as the window they cover. How many square yards of material are needed to cover this
    15·1 answer
  • A)Which would you use to solve the following system and why?
    5·1 answer
  • What is the equivalent ratio for 19:7?
    12·1 answer
  • TIME SHEET - ACTIVITY 1
    15·1 answer
  • Can you please help me
    10·1 answer
  • I need help again teehee​
    5·2 answers
  • In APQR, PR = 23 mm, QR = 39 mm, and<br> m/R = 163º.
    12·1 answer
  • SOMEONE PLSS HELP I REALLY NEED THIS I'LL GIVE BRAILIEST!! SHOW WORK PLS ONLY NUMBER 5 AND 7 THANKK UU
    8·1 answer
  • Any gymnast or cheerleader
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!