Please see pic, I'd solved in it.
Answer:
Step-by-step explanation:
The figures dont have enough letters to explain step by step all the exercises.
Bread 1:
The horizontal lines are parallels so both angles must be the same
2x + 21 = 4x - 17
21 + 17 = 4x - 2x
38 = 2x
x = 19
Bread 2:
Angles sum 180°
3y - 5 + 2y - 25 = 180
5y - 30 = 180
5y = 180 +30
5y = 210
y = 42
Bread 3:
Angle ABC is the same as the other 2, since x = 19
ABC = 2x + 21
ABC = 2 * 19 + 21
ABC = 59
Bread 4:
Angle ABC is the same as 3y - 5, y = 42
ABC = 3y - 5
ABC = 3 * 42 -5
ABC = 121
Bread 5:
Angles must be the same
5x - 14 = 2x + 13
5x - 2x = 13 + 14
3x = 27
x = 9
Bread 6:
Angle ABC = 5x - 14 , x = 9
ABC = 5 * 9 - 14
ABC = 31
If you need to understand why the angles must be the same just comment and I will give you more details
Answer:
The selected option
Step-by-step explanation:
Coincidentally, you answered correctly.
From the values of 3 and five, we can assume that the function of the table is Y=x+2.
But if we move to the next value pairs, that function is false.
10=6+2 that isn't correct.
If you apply this to all the pairs in the table you will find that there is not a function that represents the values given. Therefore, the first option is correct.
Answer:
-262
Step-by-step explanation:
Evaluate Subtraction & Addition from right to left [or left to right, as long as you know what you are doing]:
38 + 16 - 12 - 2 - 302
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I am joyous to assist you anytime.
9514 1404 393
Answer:
D.) a+2b
Step-by-step explanation:
The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...
A) 3(0) = 0 . . . even
B) 1 +3 = 4 . . . even
C) 2(1+0) = 2 . . . even
D) 1 +2(0) = 1 . . . odd
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<em>Additional comment</em>
These rules apply to even/odd:
- odd × odd = odd
- odd × even = even
- even × even = even
- odd + odd = even
- odd + even = odd
- even + even = even
Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.
