How do i solve 4x^2-9?
2 answers:
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Answer:
r = 120t/(120-t)
Step-by-step explanation:
Multiply by the denominator, isolate r terms, then divide by the coefficient of r.
Answer:
a) n<1 and n>5
b) 0 < n < -4
c) n > 2 and n < -2
Step-by-step explanation:
The signal is given by x[n] = 0 for n < -1 and n > 3
The problem asks us to determine the values of n for which it's guaranteed to be zero.
a) x[n-2]
We know that n -2 must be less than -1 or greater than 3.
Therefore we're going to write down our inequalities and solve for n
Therefore for n<1 and n>5 x [n-2] will be zero
b) x [n+ 3]
Similarly, n + 3 must be less than -1 or greater than 3
Therefore for n< -4 and n>0, in other words, for 0 < n < -4 x[n-2] will be zero
c)x [-n + 1]
Similarly, -n+1 must be less than -1 or greater than 3
Therefore, for n > 2 and n < -2 x[-n+1] will be zero