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pav-90 [236]
3 years ago
10

How do i solve 4x^2-9?

Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0
Use the PEMDAS method!
Irina18 [472]3 years ago
3 0

Answer:

x = 3/2 or x = -3/2

Step-by-step explanation:

Solve for x over the real numbers:

4 x^2 - 9 = 0

The left hand side factors into a product with two terms:

(2 x - 3) (2 x + 3) = 0

Split into two equations:

2 x - 3 = 0 or 2 x + 3 = 0

Add 3 to both sides:

2 x = 3 or 2 x + 3 = 0

Divide both sides by 2:

x = 3/2 or 2 x + 3 = 0

Subtract 3 from both sides:

x = 3/2 or 2 x = -3

Divide both sides by 2:

Answer:  x = 3/2 or x = -3/2

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Find the difference: -2/5-(-4/5)
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2/5

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x = 3

Step-by-step explanation:

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Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

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And we can solve this using the fundamental theorem of calculus like this:

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