Answer:
295/72
Step-by-step explanation:
Answer:
B=![\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's do the multiplication AB.
If A=![\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.
the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.
the second row of A is= (0 0) by any colum of B is equal to zero too.
So we have found an example that works!
Answer:
The 9th term would be 10.
Step-by-step explanation:
Each of the odd terms is 2 more than the previous. We do not even need to look at the even terms to find the 9th one.
2, odd, 4, odd, 6, odd, 8, odd, 10
Answer= 6.5y+12
distribute the 5 in the parentheses:
(-6y-3) + (15+12.5y)
(you can take away the parentheses after this step)
then add like terms together.
12.5y + (-6y) = 6.5y
15 + (-3) = 12
make it one expression.
6.5y + 12
Answer : X^2+6x+9
(X+3)(x+3)