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astra-53 [7]
3 years ago
10

Álgebra 1 please help!!!

Mathematics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

a. geometric sequence

b. a<em>n</em> = 5(2)^n-1

c. a<em>n+1 </em>= a<em>n</em> x 2

Step-by-step explanation:

The sequence: 5, 10, 20, 40,...

a. The sequence is geometric because the sequence has a common ratio of 2, each number is made by multiplying the previous number with the common ratio (2).

b. The explicit formula for this sequence is a<em>n </em>= 5(2)^n-1

The explicit formula for a geometric sequence is

a<em>n</em> = a<em>1</em> (r)^n-1

Substituting that with the values we know, we will get

a<em>n</em> = 5(2)^n-1

c. The recursive formula for this sequence is a<em>n+1 </em>= a<em>n</em> x 2

The recursive formula for a geometric sequence is

a<em>n+1 </em>= a<em>n</em> x r

Substituting for the values we know, we get

a<em>n+1 </em>= a<em>n</em> x 2

Let me know in the comments if you have any questions! If you could mark this answer as brainliest, I would very much appreciate it

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Answer:

Step-by-step explanation:

From the figure attached,

1). Sin(D) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

               = \frac{EF}{DF}

               = \frac{24}{26}

               = \frac{12}{13}

2). Cos(D) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

                = \frac{ED}{DF}

                = \frac{10}{26}

                = \frac{5}{13}

3). tan(D) = \frac{\text{Opposite side}}{\text{Adjacent side}}

               = \frac{EF}{DE}

               = \frac{24}{10}

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4). sin(F) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

              = \frac{DE}{DF}

              = \frac{10}{26}

              = \frac{5}{13}

5). cos(F) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

               = \frac{EF}{DF}

               = \frac{24}{26}

               = \frac{12}{13}

6). tan(F) = \frac{\text{Adjacent side}}{\text{Adjacent side}}

               = \frac{DE}{EF}

               = \frac{10}{24}

               = \frac{5}{12}

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3 years ago
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