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3 years ago

Which is true? Plssss

Mathematics

1 answer:

Masja [62]3 years ago

8 0

Answer:

the very first one 8.62<8.623

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Two central angles are listed below.

luda_lava [24]

You have to put the two angles in the same units, because now the first one is in radians and the second one in degress.

To pass 1.38 radians to degrees you can use the ratio 180° / π radian = 1.

So 1.38 radian * 180° / 3,1416 = 79 °.

So the angle in the Column A is 2° wider than the angle in the Column B.

6 0

3 years ago

Write the number 0.00003852 in standard form.

Basile [38]

Answer: 3.852

Step-by-step explanation:give me brianlest

4 0

3 years ago

Question set 1: One instructor believes that students take more than 2 classes per quarter on average. He randomly interviewed a

Sveta_85 [38]

Answer:

There is statistical evidence at 95% level to claim that students attend more than 2 classes per quarter

Step-by-step explanation:

Given that one instructor believes that students take more than 2 classes per quarter on average. Let X be the no of classes students take.

$H_0: \bar x =2\\H_a: \bar x >2$

(Right tailed test at 5% significance level)

$\bar x =2,3 \\s = 0.8$

Mean difference = $2.3-2=0.3$

Std error = $\frac{0.8}{\sqrt{24} } \\=0.1633$

Test statistic t = mean diff/std error = 1.84

p value =0.039

Since p <0.05, we reject null hypothesis.

There is statistical evidence at 95% level to claim that students attend more than 2 classes per quarter

3 0

4 years ago

-2x + 3 = -11<br> X =<br> Helpppp

Fiesta28 [93]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

8 0

4 years ago