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Bingel [31]
3 years ago
7

Himari gave birth to twins and named them Adrian and Chang. When they were first born, Adrian massed 2.87 kilograms and was 54.5

centimeters tall, and Chang massed 4.54 kilograms and was 51 centimeters tall. How much did the babies mass in total?
Mathematics
2 answers:
Likurg_2 [28]3 years ago
4 0

Answer:

The babies massed in total 7.41 kg

Step-by-step explanation:

we know that

To find out the total mass, sum Adrian's mass and Chang's mass

so

The total mass is equal to

2.87+4.54=7.41\ kg

therefore

The babies massed in total 7.41 kg

Viktor [21]3 years ago
3 0

Answer:

The total mass of the babies was 7.41 kilograms.

Step-by-step explanation:

Consider the provided information.

When they were first born, Adrian massed 2.87 kilograms and Chang massed was 4.54 kilograms.

Now we need to find How much did the babies mass in total.

For this we just need to add the numbers as shown:

 2.87

+<u>4.54</u>

 <u> 7.41</u>

Hence, the total mass of the babies was 7.41 kilograms.

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Answer:

70.622 in³

Step-by-step explanation:

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XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

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