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d1i1m1o1n [39]
3 years ago
10

Pls help me with this pls

Mathematics
1 answer:
Virty [35]3 years ago
6 0
(Sorry if I get something wrong, it’s straining my eyes to see what letter) 1. A 2. U 3. S 4. J 5. I 6. M 7. H 8. B 9. Y 10. L


To find where a coordinate is on a graph you need to start with the first number (x) (let’s say the coordinate is (2, -3), so 2) and find where it is ( you always find where the first number is on the x-axis and the second number on the y, remember that by x, y and x comes first.) Then, you need to find the second number (-3) then you need to find where they meet. So 2, -3 is on the letter I.

To find what coordinates a point that’s already been plotted is to see, for example, L, the two numbers that meet where L is are -4, -3, remember whatever was on the x axis comes first, -3, -4 is not the same.

Hopefully this makes sense, I don’t normally answer stuff.
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The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
3 years ago
What is .07 times 1.22
lidiya [134]
.07×1.22 = ?
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now add the decimals back to the answer, we had 4 decimal places in the questions so add 4 decimal places to 854 = 0.0854

answer= 0.0854
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Jalen charges customers a flat fee of $30 to mow their grass plus $8.50 an hour for additional yard work. If Mr. Williams pays J
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Answer:

She spent 2 and a half hours doing extra work.

7 0
3 years ago
Can you please please help graph the line? Thanks!!!!!
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Because we know x stays constant, draw a point on (0,5). then draw a line extending up and down from (0,5) indefinitely because no matter what y is, x always stays the same--5.

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