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fredd [130]
3 years ago
11

What's the difference between 126 1/4 and 78 2/3

Mathematics
1 answer:
anygoal [31]3 years ago
5 0
126 1/4 - 78 2/3 = ?
turn into mixed fractions
504/4 - 236/3 =?
find the least common denominator
1512/12 - 944/12 = ?
subtract
568/12
turn into improper fraction
47 1/3

The difference <span>between 126 1/4 and 78 2/3 is 47 1/3</span>
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The value of x in the expression<br> 2x/3 - 7 = 5 is
Andrej [43]

Answer:

The answer is X = 18

Step-by-step explanation:

2x/3 - 7 = 5

Multiply both sides if the equation by 3 : 2x - 21 = 15

Move the constant to the right hand side and change its sign : 2x = 15 + 21

Calculate 2x = 15 + 21

2x = 36

Divide both sides of the eqaution by 2 : 2x = 36

x = 18

Answer X = 18

3 0
3 years ago
Solve the following system:<br> y=1<br> y=-6x-5
Mandarinka [93]

Answer:

x = -1

y = 1

Step-by-step explanation:

<u><em>Since it gives you "y", plug in the number given into the equation:</em></u>

y = -6x - 5

1 = -6x - 5

<u><em>Then, add 5 to both sides:</em></u>

1 = -6x - 5

+5       + 5

________

6 = -6x

<em><u>Divide both sides by -6:</u></em>

6 = -6x

-1 = x

So now you have, x = -1 and y = 1

4 0
3 years ago
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son4ous [18]

Answer:

y=x2

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4 0
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WILL GIVE BRAINLIEST X_X
kap26 [50]

Answer:

All circles are similar. Since they are all the same shape; they are all alike. It is a property.

Step-by-step explanation:

5 0
3 years ago
A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali
Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

W = Wednesday

T = Thursday

F = Friday

S = Saturday

Their corresponding probabilities are

P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1

Since Y = number of days beyond Wednesday that it takes for both magazines to arrive(so possible Y values are 0, 1, 2 or 3)

The possible number of outcomes are therefore 4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)

The values associated for each of the outcomes are as follows:

Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3

The probability mass function of Y is,

P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19

7 0
3 years ago
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