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Makovka662 [10]
3 years ago
5

What is the interval notation for the compound inequality? x ≤ −4 or x ≥ 5

Mathematics
1 answer:
torisob [31]3 years ago
8 0

Answer:

(-∞, -4] ∪ [5, ∞)

Step-by-step explanation:

Hi!

Alright, so greater (or less) than or equal to is denoted with a bracket.

If x is less than or equal to -4, then the bracket is on the left side.

(___, -4]

Because x is <em>any</em> number under or equal to -4, x can range from negative infinity. However, we use a parentheses for infinity because infinity can never truly be reached.

So, x \leq -4 = (-∞, -4]

X\geq5

Equal to = bracket

X is any number above 5, so

[5, ∞)

Because we want both of these, we use the union sign (∪)

so,

= (-∞, -4] ∪ [5, ∞)

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laila [671]

<span>Volume of the pyramid = (1/3) * base area * height
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6 0
3 years ago
In an arithmetic series, if the fifth term is 74 and the twelfth term is 116, find the sum of the first 30 terms.
Assoli18 [71]
If you know the formula of a given arithmetic series, it is (first term + last term)*(number of terms)/2. we already know we want the first 30 terms so number of terms = 30. now we should try to find the first and last term. we can do that by finding the d, or the distance between each successive term. this is:
(116 - 74)/(12 - 5) = 6.
now we can find the first term. the fourth term is 74 - 6, the third term is 74 - 2(6), the second term is 74 - 3(6) and the first term is 74 - 4(6) = 50. 
now using the first term, we can find the last term. the last term is the 30th term and to get that number, some might think it is:
50 + 30(6)
but take a look at the second term, it is
50 + 6
and the third term, it is
50 + 2(6)
basically the nth term is
50 + (n-1)(6)
so the 30th term is:
50 + 29(6) = 224
now we can compute what we want:
(224 + 50)(30)/2 = 4110

now you may be wondering why the formula is the way it is. there is actually a story associated with this. there was a famous mathematician named carl friedrich gauss. legend has it that when he was a kid, once when he was in school, the teacher wanted to slack off, so he (or she...idk which one) told all his (her) students to add the numbers from 1 to 100. everyone instantly went 1+2 = 3, 3 + 3 = 6, 6 + 4 = 10, etc. carl, on the other hand, applied a neat trick that got him the answer really quickly. he wrote the integers from 1 to 100 then wrote that same sequence below it but in reverse order. so:
1,      2,   3,   4,    5, ...,   95, 96, 97, 98, 100
100, 99, 98, 97, 96, 95...5,    4   3,   2,   1
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a,   a+d,    a+2d...    a+(n-2)d, a+(n-1)d
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let me know if you have any questions!!! 
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Answer:

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Step-by-step explanation:

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