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Kay [80]
3 years ago
5

Taylor wants to center a 3.5 inch picture on a piece of paper that is 12 inches wide How

Mathematics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

The picture is 4.25 inches from the side of the paper

Step-by-step explanation:

- Taylor wants to center a 3.5 inch picture on a piece of paper that is

12 inches wide

- Lets think about that he want to put the picture in the center of the

paper, then divide the length of the paper into two equal parts and the

picture into two equal part

∵ The width of the paper is 12 inches

∵ 12 ÷ 2 = 6 inches

∵ The width of the picture is 3.5 inches

∵ 3.5 ÷ 2 = 1.75

- Now lets subtract from 6 inches (half paper) 1.75 inches (half picture)

to find the distance between the side of the paper and the picture

∵ 6 - 1.75 = 4.25

∴ The distance from the side of the paper to the picture is 4.25 inches

* <em>The picture is 4.25 inches from the side of the paper</em>

* Look to attached figure for more understand

Ede4ka [16]3 years ago
4 0

Answer:

The picture needs to be 4.25 inches far from the side of paper.

Step-by-step explanation:

Width of the picture = 3.5 inches

Width of paper piece = 12 inches

Since , the picture is to be placed in center of the paper. So, the distance from both opposites sides will be equal say x.

Width of paper piece = x + Width of the picture + x

12 inches = x + 3.5 inch + x

12 inch = 3.5 inch + 2x

x=\frac{12 - 3.5}{2} inches=4.25 inches

The picture needs to be 4.25 inches far from the side of paper.

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Find the lengths of the missing side . Simplify all radicals !!!<br> help mee!!!!!!
larisa86 [58]

Answer:

e = 13\sqrt{2}

f = 13\sqrt{2}

Step-by-step explanation:

The ∆ given is an isosceles ∆ with a right angle measuring 90°, and two congruent angles measuring 45° each.

Using trigonometric ratio formula, we can find the lengths of the missing side as shown below:

Finding e:

sin(\theta) = \frac{opp}{hyp}

sin(\theta) = sin(45) = \frac{\sqrt{2}}{2}

hyp = 26

opp = e = ?

Plug in the values into the formula

\frac{\sqrt{2}}{2} = \frac{e}{26}

Multiply both sides by 26

\frac{\sqrt{2}}{2}*26 = \frac{e}{26}*26

\frac{\sqrt{2}}{2}*26 = e

\frac{\sqrt{2}}{1}*13 = e

13\sqrt{2} = e

e = 13\sqrt{2}

Since side e is of the same length with side f, therefore, the length of side f = 13\sqrt{2}

3 0
3 years ago
18. What is the area of a piece of garden plot 5 yards 2 feet long by 6 yards 1 foot wide? Give your answer in square feet.
34kurt

Answer:

<h2>C. 323 ft²</h2>

Step-by-step explanation:

1 yard = 3 feet

5yd 2ft = (5)(3)ft + 2ft = 17ft

6yd 1ft = (6)(3)ft + 1ft = 19ft

The formula of an area of a rectangle:

A = wl

w - width

l - length

Substitute w = 19ft and l = 17ft:

A = (19)(17) = 323 ft²

5 0
3 years ago
A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g
miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

{0.2}\times{62} = 12.4

{0.2}\times{83} = 16.6

{0.2}\times{91} = 18.2

{0.25}\times{88} =22

Now, by adding the scores to get the average score

We get, 69.2.

6 0
3 years ago
1.) Use a property to write an equivalent expression for 12*(100-5). Which property did you use?
Jlenok [28]

1. 12*100 - 12*5

You would use the distributive property to get this equation (it is equivalent to the original one)

2. Um... There's no actual story for this problem; sorry I can't solve this problem



3 0
3 years ago
Read 2 more answers
Mariah was playing a game where she gets a point if her spinner lands on a multiple of 3. What is the probability that she will
DedPeter [7]

Answer:

She has a 67% chance of getting anything other than a multiple of 3.

Step-by-step explanation:

8 to 4

7 0
3 years ago
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