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Andreas93 [3]
3 years ago
7

A system administrator needs to create a high-performance SQL server. What type of disk configuration will allow the administrat

or to connect an offline physical disk that is connected to the host machine to a VM to maximize a VM's performance?
Computers and Technology
1 answer:
Studentka2010 [4]3 years ago
4 0

Answer:

Pass-through disk

Explanation:

Pass-through disk configuration will allow the administrator to connect an offline physical disk that is connected to the host machine to a VM to maximize a VM's performance.

VMs access a physical hard disk by way of a "pass-through disk," a special virtual disk that directly accesses the physical disk if it is made exclusively available to the VM.

A pass-through disk must be offline in the parent partition of the Hyper-V server.

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2. Write a program with a function that accepts a string as an argument and returns a copy of the string with the first characte
Oduvanchick [21]

Answer:

Following are the code to this question:

def capital(val):#defining a method that takes string value as parameter

   x=True#defining boolean variable

   r=''#defining string variable  

   for i in val:#defining loop to convert the first character into upper case

       if i.isalpha() and x:#defining condition to check input value is string

           r=r+i.upper()#change value into uppercase and hold value in r variable

           x=False#assign value false in boolean variable

       elif i=='.' or i=='?' or i=='!':#check symbols

           r=r+i#add value in r variable

           x=True#assign value True in boolean variable

       else:

           r=r+i#add all value in r variable

   return r#return r variable value

val=input()#input value in val variable

print(capital(val))#called the function which print the return value

Output:

please find the attachment.

Explanation:

  • In the above python program, a method "capital" is declared, which accepts a "val" a string value in its parameter, and inside the method one boolean "x" and one string "r" variable is used, in which r stores return value.
  • In the next step, for loop is declared, inside the loop, the conditional statement is used, in if the block it checks string value and converts the first character into upper case and assigns value false in the boolean variable.  
  • In the next step, elif block is defined that adds value in r variable and at the last, it will return function value, at the last step "val" variable is declared that input value from the user and pass into the method and print its return value.

4 0
3 years ago
Which selection below has the greatest storage capacity
shutvik [7]
Where is the selection?

Message me when you have the full question.
8 0
3 years ago
The undo button allows you to reverse up to ____ previous actions, one at a time.
Maurinko [17]
The undo button allows you to reverse up to 100 previous actions, one at a time.<span> The undo button is found in the toolbar. It erases the last change done to the document reverting it to an older state.</span><span> The change can be formatting text, moving blocks, typing and deleting text.

</span>
6 0
3 years ago
Which of the following statements does not explain the difference between safety stock
ioda

The statements does not explain the difference is that Cross-docking reduces inventory and storage space requirements, but handling costs and lead times tend to increase.

<h3>What is the difference between safety stock inventory and the cross-docking method?</h3>

safety stock inventory is known to be a kind of traditional warehousing systems that needs  a distributor to have stocks of product already at hand to ship to their customers.

But  a cross-docking system is one that is based on using the new and best input such as technology and business systems to produce a JIT (just-in-time) shipping method.

Learn more about safety stock Inventory from

brainly.com/question/18914985

6 0
2 years ago
Write two recursive versions of the function minInArray. The function will be given a sequence of elements and should return the
Viktor [21]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;//using namespace

int minInArray1(int arr[],int arrSize)//declaring method minInArray1

{

if(arrSize == 1)//use if block to check arrSize value is equal to 1  

{

return arr[0];//return first element of array

}

else //defining else block

{

int max= minInArray1(arr, arrSize-1);//use integer variable max to call method recursively  

if(arr[arrSize-1] < max)//use if block to check array value  

{

max = arr[arrSize-1];//use max to hold array value

}

return max;//return max variable value

}

}

int minInArray2(int arr[], int low, int high)//defining a method minInArray2  

{

if(low == high) //use if to check low and high variable value are equal

{

return arr[low];//return low variable value

}

else //defining else block

{

int minimum = minInArray2(arr, low+1, high);//defining integer variable minimum to call method minInArray2 recursively

if(arr[low] < minimum)

{

minimum = arr[low];//use minimum variable to hold array value

}

return minimum;//return minimum value

}

}

int main()//defining main method

{

int arr[10] = { 9, -2, 14, 12, 3, 6, 2, 1, -9, 15 };//defining an array arr

int r1, r2, r3, r4;//defining integer variable

r1 = minInArray1(arr, 10);//use r1 variable to call minInArray1 and hold its return value

r2 = minInArray2(arr, 0, 9);//use r1 variable to call minInArray2 and hold its return value

cout << r1 << " " << r2 << endl; //use print method to print r1 and r2 variable value

r3 = minInArray2(arr, 2, 5);//use r3 variable to call minInArray1 and hold its return value

r4 = minInArray1(arr + 2, 4); //use r4 variable to call minInArray2 and hold its return value

cout<<r3<< " " <<r4<<endl; //use print method to print r3 and r4 variable value

return 0;

}

Output:

please find the attached file.

Explanation:

In the given code two methods, "minInArray1 and minInArray2" is defined,  in the "minInArray1" it accepts two-variable "array and arrSize" as the parameter, and in the "minInArray2" method it accepts three integer variable "array, low, and high" as the parameter.

  • In the "minInArray1" method, and if the block it checks array size value equal to 1 if the condition is true it will return the first element of the array, and in the else block the max variable is defined, that calling method recursively
  • and store its value.
  • In the "minInArray2" method, an if the block it checks low and high variable value is equal. if the condition is true it will return a low array value. In the next step, the minimum value is defined, which checks the element of the array and uses a low array to store its value.
  • In the main method an array and four integer variable "r1, r2, r3, and r4" is defined, which calls two methods "minInArray1 and minInArray2" and use print method to print its value.
7 0
3 years ago
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