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Otrada [13]
3 years ago
14

Find a unit vector that is orthogonal to both i + j and i + k.

Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer: i - j - k

Step-by-step explanation:

Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.

<1,1,0> x <1,0,1>

det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )

the determinate of the matrix: <1,-(1),-1>

or: i - j - k

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Help<br> I’m in middle of test
azamat

Answer:

486

Step-by-step explanation:

It will be the third one I think because that on is 486 and it seems ro be the correct answer since the sides are nine. Good luck!

5 0
3 years ago
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Directed line segment overline FG has endpoints F(4, 9) and G(- 8, - 9) .On the coordinate plane below , plot a point that parti
Thepotemich [5.8K]

Answer:

The coordinates of the point that makes the division in the given ratio is (0,3)

Step-by-step explanation:

Here, we want to find the point on the line segment that divides the line segment in the ratio 1:2

We simply use the internal division formula

That would be;

(x,y) = (nx1 + mx2)/(m + n) , (ny1 + my2)/(m + n)

m = 1 and n = 2

(x1,y1) = (4,9)

(x2,y2) = (-8,-9)

Substituting these values into the formula, we have;

2(4) + 1(-8)/(1 + 2) , 2(9) + 1(-9)/(2 + 1)

= (8-8)/3 , (18-9)/3

= (0,3)

5 0
3 years ago
Construct an equilateral triangle of side 7cm and construct circumcircle.
zalisa [80]

Answer:

To do this, all you need is to draw triangle with each side being 7 cm, and a circle that intersects all three of its corners.

Step-by-step explanation:

  1. With a ruler and a pencil, draw a 7cm line.
  2. With a compass set to a radius of 7cm draw an arc centered around the right end of the line.
  3. With the same compass, still at 7cm, draw an arc centered around the left end of the line.
  4. These two arcs will intersect on either side of the line (you only need one side, so you only need a small arc in the right place, roughly where you think the third point if the triangle is.
  5. Where those arcs intersect is the third point on your triangle.  Mark that, and then trace two lines from that point to either end of the line segment you started with.

<em>You now have an equilateral triangle with 7cm sides.  Next you need to draw the circle</em>

  1. Measure the halfway point on two of your three lines.
  2. Draw a line from that each of those halfway points to the opposite corner. The new lines you're drawing will be perpendicular to the edge your measuring against.
  3. You have now drawn two line segments, and they intersect in the center of the circle.  Now take your compass and set its radius to the distance from that center point to one of the three corner points.
  4. Centered on that middle point, trace a circle with the selected radius.

And you're done!

6 0
3 years ago
Answer the question on the attachement
Mama L [17]
Answer: 6 cups of water
7 0
3 years ago
What is the asnwer worked out to m-9=-13
Natalija [7]
Thus is a linear equation, so you want to isolate m so you can compare the variable m to a constant.

You begin by getting rid of -9 by adding 9 (its opposite) since a negative plus a positive can me zero. Then you add 9 to (-13) which is the same as 13-9 but with a negative value, so you get -4.

The answer is -4

8 0
4 years ago
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