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Sedbober [7]
3 years ago
9

what two tools and or resources will be helpful to you in your professional or academic experiences? ​

Mathematics
1 answer:
notsponge [240]3 years ago
3 0

Answer:

SOWT analysis and career testing I think

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Factor the polynomial: 3x2(x -4) - 5(x - 4)
DIA [1.3K]
B. (x-4)(3x2-5)
your welcome
7 0
2 years ago
Solve the system of equations y = x + 5 and y = 5x - 11 using a graphical method.
tresset_1 [31]

You can use substitution for this.

x+5 = 5x -11

Combine like terms

16=4x

Divide 4 on both sides to isolate the x

x=4

Plug x=4 to one of the equations

y= 4 +5

Combine like terms

y=9

So the answer is A. (4,9)

I hope this helps you out a bunch hun :)

4 0
3 years ago
You start driving north for 16 miles, turn right, and drive east for another 30 miles. At the end of driving, what is your strai
Maru [420]

The distance between starting and ending point is 34 miles.

Step-by-step explanation:

Given,

Car moves 16 miles to north then 30 mile to east.

It forms a right angle triangle.

The straight line distance from starting to ending point represents hypotenuse.

To find the distance between starting and ending point.

Formula

By <em>Pythagoras theorem,</em>

h² = b²+l² where h is the hypotenuse, b is base and l is the another side.

Taking, b=16 and l=30 we get,

h² = 16²+30²

or, h = \sqrt{256+900}

or, h = \sqrt{1156} = 34

Hence,

The distance between starting and ending point is 34 miles.

5 0
3 years ago
I have to solve this<br>4x-5=2-x​
9966 [12]

Answer:x=7/5

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
2 years ago
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