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Sedbober [7]
2 years ago
9

what two tools and or resources will be helpful to you in your professional or academic experiences? ​

Mathematics
1 answer:
notsponge [240]2 years ago
3 0

Answer:

SOWT analysis and career testing I think

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A change machine can accept $1, $5, $10, and $20 bills and returns quarters. What is the domain and range of this situation?
Svet_ta [14]

Answer:

Domain {1,5,10,20}

Ranger {4,20,40,80}

Step-by-step explanation:

$1=4 quarters

$5=20 quarters

$10=40 quarters

$20=80 quarters

Domain {1,5,10,20}

Ranger {4,20,40,80}

5 0
3 years ago
Two automobiles start together at the same place and travel along the same route. the first averages 40 miles per hour, the seco
erastovalidia [21]

55 mph minus 40 mph = 15 miles distance for each hour


So 5 hours * 15 = 75 miles difference after 5 hours



3 0
3 years ago
Read 2 more answers
Solve x^2-3x-20=8 for quadratic equation​
snow_lady [41]

Answer:

x = -7

x = 4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
NEED HELP WITH THESE QUESTIONS
amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =

Applying double C we have:

\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =

Canceling common terms:

\frac {mn ^ 5} {p ^ 4}

Answer:

Option A

Question 2:

We should simplify the following expression:

\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}

So, we have:

\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =

Simplifying common terms:

\frac {1} {y ^ 2z ^ 2}

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

<em>r ^ 2 + 7r + 10: </em>We look for two numbers that multiplied give 10 and added 7:

(r + 5) (r + 2)

<em>r ^ 2-5r-50:</em> We look for two numbers that multiplied give -50 and added -5:

(r-10) (r + 5)

<em>3r-30 = 3 (r-10)</em>

Rewriting the given expression we have:

\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =

We simplify common terms in the numerator and denominator we have:

(r + 2)

Answer:

Option D

4 0
2 years ago
Read 2 more answers
(X+5)(x-3) Find the product
Allisa [31]

Answer:

(x-3) (x+5) => x*x+5x-3x-15

=> x*x+2x-15

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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