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xxTIMURxx [149]
3 years ago
15

Jessica draw circle divided into eight equal parts she cheated six of the parts what fraction is equivalent to the part of The c

ircle that is shaded
Mathematics
2 answers:
tia_tia [17]3 years ago
7 0
6:8=3:4
we divide 6 with 8 then we get new ratio 3:4

mr Goodwill [35]3 years ago
4 0
If she has 8 parts and 6 parts are shaded in then she has a fraction of 6/8 and if u divide 6 and 8 by 2 you get 3 and 4 or a fraction of 3/4
You might be interested in
Twice the sum of a number and 8 is the same aa the difference of 3 and the number. Find the equation that could be used to find
Nezavi [6.7K]

Answer:

f your number is x, then the difference between that number and 8 would be x-8. Twice that is 2(x-8)

 

Three times the sum of the number and 3 would be 3(x+3). So, you get the equation:

 

2(x-8)=3(x+3)

2x-16=3x+9

x=-25

5 0
3 years ago
What are the domain values for the function f(x) = 2x + 3 if the range values are (-1, 1, 2,4}
ArbitrLikvidat [17]

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

So i think it will be -1

7 0
3 years ago
Determine if function. HELLPPP If you awnser correctly i will try and give you a brainlyyyy.​
astraxan [27]

Answer: This relation is not a function

Step-by-step explanation:

To find out if a relation is a function, we need to use the vertical line test, which means each input value only has one output value. This graph does not pass that vertical line test.

7 0
3 years ago
Read 2 more answers
How to write a expression for: Jasmin has increased her $45 by m dollars and then spends a third of the entire amount.
siniylev [52]
The first part is addition.
45+m
If she spend a third of it, you could multiply by 1/3 or divide by 3.
Multiply: 45+m x 1/3
Divide: 45+m/3
6 0
3 years ago
ASAP! I really need help with this question! No nonsense answers, and please attach the solution.
uysha [10]

Answer:

\boxed{\sf Option \ 4}

Step-by-step explanation:

\sqrt{2x-3} +x=3

Subtract x from both sides.

\sqrt{2x-3} +x-x=-x+3

\sqrt{2x-3}=-x+3

Square both sides.

( \sqrt{2x-3})^2 =(-x+3)^2

2x-3=x^2-6x+9

Subtract x²-6x+9 from both sides.

2x-3-(x^2-6x+9 )=x^2-6x+9-(x^2-6x+9)

-x^2 +8x-12=0

Factor left side of the equation.

(-x+2)(x-6)=0

Set factors equal to 0.

-x+2=0\\-x=-2\\x=2

x-6=0\\x=6

Check if the solutions are extraneous or not.

Plug x as 2.

\sqrt{2(2)-3} +2=3\\ \sqrt{4-3} +2=3\\\sqrt{1} +2=3\\3=3

x = 2 works in the equation.

Plug x as 6.

\sqrt{2(6)-3} +6=3\\ \sqrt{12-3} +6=3\\\sqrt{9} +6=3\\3+6=3\\9=3

x = 6 does not work in the equation.

5 0
4 years ago
Read 2 more answers
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