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Aleks [24]
3 years ago
6

I need help?!! Answer quicklyy

Mathematics
1 answer:
Kisachek [45]3 years ago
8 0

Answer:

-7

Step-by-step explanation:

To find f(-8), use the blue line labeled f(x) and go to -8 on the x axis and find its corresponding y value by moving vertically down from -8 to the blue line and find the y value of that point. You can see that the blue line hits (-8, -5) so the y value is -5 and f(-8) = -5.

Do the same thing for g(4) and you should find the red graph g(x) hits the point (4, 3). So g(4) = 3.

-1 * -5 - 4 * 3 = 5 - 12 = -7

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Need help asap please no scammers!!!!!!!!!!!!!!!
galina1969 [7]

Answer:

111

Step-by-step explanation:

u got scammed

4 0
3 years ago
80km is 9% of what distance?
seropon [69]

Answer:

  888.89 km

Step-by-step explanation:

Write the given question as an equation and solve.

  80 km = 0.09 × (what distance)

  (80 km)/0.09 = what distance . . . . . divide by the coefficient of the variable

  888.89 km ≈ what distance

80 km is 9% of 888.89 km

3 0
2 years ago
8.5+4(1-2.5k)=24.5 round to the nearest hundredth
frosja888 [35]
Hi there! 

Your question: 

8.5 + 49(1-2.5k)=24.5

My answer: 

8.5 + 4(1-2.5k) = 24.5 >>>>>>> first, you have to distribute

8.5 + 4 - 10k = 24.5 >>>>>>>> now, we are going to combine like terms.

12.5 - 10k = 24.5 >>>>>> now, we are going to subtract 12.5 on both sides 

-10k = 12 >>>>>>>>> finally, divide -10 on both sides

k = -1.2


Hope this helps you!


7 0
3 years ago
Read 2 more answers
The number 3.14 is a rounded value of the mathematical quantity pi. If you replace 3.14 with pi what is the exact formula for th
____ [38]

C = πd ( in terms of the diameter ), C = 2πr ( in terms of the radius )


6 0
3 years ago
In Canada in 1998 the estimated number of households that owned 2 or more vehicles was 3.939 x 10 6
WITCHER [35]

In Canada in 1998 the estimated number of households written in standard decimal notation is 3939000

<u>Solution:</u>

Given that in 1998 estimated number of households that owned 2 or more vehicles was 3.939 \times 10^{6}

Need to represent the number 3.939 \times 10^{6} in standard decimal notation.

In this case we need to move the decimal point based on the power of 10.

In our case power of 10 = 6.

Let’s first take a number without 10^6 and add six zeros on right.

So we get 3.939000000

Now multiplying above number by 10^6 means moving the decimal after 6 numbers from the current position, that means  

3.939 \times 10^{6}=3939000.00

That is 3939000 is required standard decimal notation of scientific notation number 3.939 \times 10^{6}

5 0
3 years ago
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