Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
I think its the... second.... please correct me if im wrong :(
Step-by-step explanation:
- 1⅔ < -¼
__________________
If that's an addition sign, then b=-35.
If it's a division sign, then b=-150
Sorry I can't see which it is! Hope this helped though :)
Good luck!
Answer:
Hence the 3.28 %or 2/61 of total work will be done .
Step-by-step explanation:
Given:
The pecan crops are harvested for friday and saturday (2days)
To find :
What fraction these 2 days corresponds to the harvesting days?
Solution;
The pecan crops are growing in America in state of Georgia
and consider that in months of October and November pecan crop becomes mature .
Hence the harvesting period is of 2 months considerably .
The month of October and November days are 31 and 30 .
Hence the Total days of harvesting are 61 days.
In these days total Pecan crops will be harvested.(100% work in 61 days)
Now the farmer harvest for 2 days only .
Required fraction=2/61
=0.0327869
=3.28%
Depending upon the crop field and planting answer will vary
But 3.28 % of total work will be done in 2 days on harvesting
