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3 years ago

12

What is the equation of the graph?

1 answer:

ra1l [238]3 years ago

4 0

The general shape is that of an exponential function. Since the horizontal asymptote is -3, it appears to be shifted down 3. The y-intercept is 1 unit above the horizontal asymptote, so it appears there has been no horizontal shift.

For x=1, the curve goes through a point 6 units above the horizontal asymptote. This suggests the equation is
y = 6^x - 3

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How do you right -6x-42=-16y in standard form?

Vinil7 [7]

16y=6x+42
16/16y=6x/16+42/16
y= 3x/8 + 21/8

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Rosa Roberto Andrea and innocent find an estimate for square root of 10

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The square root of 10 is 3.1 but to estimate it find the square root of 9 which is 3

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3 years ago

A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi

rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

$P(9$

Recall Chebyshev's inequality that

$P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\$

Comparing with the Ii equation which is appropriate here we find that

$\mu =14.5$

Next what we find is

$k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071$

Thus from the given information we find that

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4 years ago

Solve the equations for all values of x by completing the square x^2+62=-16x

lorasvet [3.4K]

Answer:

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Step-by-step explanation:

To complete the square, we first have to get our equation into $ax^2 + bx = c$ form.

First we add 16x to both sides:

$x^2 + 16x + 62 = 0$

And now we subtract 62 from both sides.

$x^2 + 16x = -62$

We now have to add $(\frac{b}{2})^2$ to both sides of the equation. b is 16, so this value becomes $(16\div2)^2 = 8^2 = 64$ .

$x^2 + 16x + 64 = -62+64$

We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because $8\cdot8=64$ and $8+8=16$ .

$(x+8)^2 = -62 + 64$

We can now take the square root of both sides.

$x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}$

We can now isolate x on one side by subtracting 8 from both sides.

$x = \pm\sqrt{2} - 8$

So our solutions are

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Hope this helped!

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3 years ago

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