Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
Therefore, the coefficients of the expansion are given by:
1, 6, 15, 20, 15, 6, 1
Answer:
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
(1 7/10) / (3/5)
(17/10) / (3/5) =
17/10 * 5/3 =
85/30 =
2 5/6........yes, because 1 7/10 divided by 3/5 = 2 5/6...answer C
Answer:
z = 66
Step-by-step explanation:
RS = z
QT = z - 33
Based on the midsegment theorem, QT = ½(RS)
Plug in the values
z - 33 = ½(z)
Multiply both sides by 2
2(z - 33) = z
2z - 66 = z
Add 66 to both sides
2z = z + 66
Subtract z from both sides
2z - z = 66
z = 66
Answer:
$4.35
Step-by-step explanation:
The expected value of a random variable <em>X</em>, often denoted as E(<em>X</em>), indicates the probability-weighted average of all possible values/events. The general formula of expected value is
.
Therefore, the expected value of the winnings from a game is
.
45 Cards
12 friends invited; 1/2 came 12 x 1/2=6
Let x stand for the number of cards each friend received
Armando kept 3
6x = 45-3
6x = 42
__ __
6 6
x = 7
Each friend received 7 cards
