All categories

3 years ago

To which graph does the point (8, -2) belong?

Mathematics

2 answers:

valentinak56 [21]3 years ago

7 0

Since x is positive and y is negative, this is Quadrant IV.
Just graph the point, and see where it is.

poizon [28]3 years ago

4 0

4 quadrant because on a graph a + and + are 1 then a - and a + are 2 then a - and a - are 3

You might be interested in

A small cube with side length 6y is placed inside a larger cube with side length 4/2. What is the difference in the

Leokris [45]

Answer:

Step-by-step explanation:

Side length of a small cube = 6y

Side length of a larger cube = 4x²

This small cube is placed inside a larger cube. We need to find the difference in the volume of the cubes.

Volume of small cube, $V_1=(6y)^3=216y^3$

Volume of lager cube,

$V_2=(4x^2)^3\\\\=64x^6$

Difference in the volume of the cubes,

$\Delta V=V_2-V_1\\\\=64x^6-216y^3$

We can simplify the above expression :

$\because \ (a^3-b^3)=(a-b)(a^2+ab+b^2)\\\\(4x^2)^3-(6y)^3=(4x^2-6y)((4x^2)^2+4x^2\times 6y +(6y)^2)\\\\=(4x^2-6y)(16x^4+24x^2y+36y^2)$

So, the difference in the volumes of the cubes is $(4x^2-6y)(16x^4+24x^2y+36y^2)$ .

3 0

3 years ago

When solving a system of equations graphically, when would you need to estimate the solution? Explain

SashulF [63]

Answer:

To solve an equation means to find all the values that should satisfy the given statement. To solve an equation graphically, draw the graph for x and y of the given equation and notice where the curves cuts should be equal.

Step-by-step explanation:

Solving system of linear equations by using graph:

A system of linear equations contains atleast two equations.For example y=5x+2 and y=x.The solution of both equations can be denoted as a ordered pair.To solve the system of linear equations we have to plot the points in the graph for both equations in coordinate system must be same.The intersection of two straight lines is the solution(point) for the given system.

8 0

3 years ago

Read 2 more answers

Please help me ! Today 11/6/2020 :(

dangina [55]

I believe the answer is c, TSR

5 0

3 years ago

About A red and a blue die are thrown. Both dice are fair. The events A, B, and C are defined as follows: A: The sum on the two

Flauer [41]

$p(A) = \frac{1}{2}$

$p(B) = \frac{1}{6}$

$p(C) = \frac{1}{6}$

$P(A | C)=\frac{1}{2}$

Solution:

The probability of an event is given as:

$\text { probability of an event }=\frac{\text { number of favorable outcomes }}{\text { total number of outcomes }}$

In throwing one die, the total number of outcomes = 6 { 1, 2, 3, 4, 5 , 6}

First let us calculate p(A):

The event is defined as: The sum on the two dice is even

Sum on two dice is even if and only if either both dice turn up odd or both even.

The odd outcomes in thowing a single die = 3 {1, 3, 5}

The even outcomes in throwing a single die = 3 {2, 4, 6}

The probability that both turn up odd is:

$\text { probability of both die turing up odd }=\frac{3}{6} \times \frac{3}{6}=\frac{1}{4}$

Similarly, the probability that both turn up even is:

$\text { probability of both die turing up even }=\frac{3}{6} \times \frac{3}{6}=\frac{1}{4}$

probability that the sum on two dice is even = probability that both turn up odd + probability that both turn up even

$\text { probability of sum on two dice is even }=\mathrm{p}(\mathrm{A})=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}$

Thus $p(A) = \frac{1}{2}$

Let us calculate p(B):

The event B is defined as: The sum on the two dice is at least 10

The total possible outcomes of two die is given as:

{(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Since each individual die can turn up any of the numbers 1, 2, 3, 4, 5, 6 the event "sum of the two dice will be at least 10" is :

atleast 10 means that sum can be 10 or greater than 10

{(4,6), (6,4), (5,5), (5,6), (6,5), (6,6)}

Here favourable outcomes = 6

Total number of outcomes = 36

Hence, the probability that the sum of the two dice will be at least 10 is:

$\text { probability that the sum of the two dice will be at least } 10=\frac{6}{36}=\frac{1}{6}$

Thus $p(B) = \frac{1}{6}$

Let us calculate p(C):

The event C is defined as: The red die comes up 5

Favourable outcomes = {(1,5),(2,5),(3,5),(4,5),(5,5),(6,5)}

$\text { probability of red die comes up } 5 \text { is the event }=\frac{6}{36}=\frac{1}{6}$

Thus $p(C) = \frac{1}{6}$

B) What is p(A l C)

$P(A | C)=\frac{p(A \cap C)}{P(C)}$

$\mathrm{A} \cap \mathrm{C}=\{(1,5),(3,5),(5,5)\}$

$p(A \cap C)=\frac{3}{36}=\frac{1}{12}$

$P(A | C)=\frac{p(A \cap C)}{P(C)}=\frac{\frac{1}{12}}{\frac{1}{6}}=\frac{1}{2}$

Thus $P(A | C)=\frac{1}{2}$

8 0

4 years ago

A study showed that there are 16 vehicles for every 10 households. How many vehicles are there for 107 million households?

Komok [63]

$16v........10h \\x......107.000.000h \\\\ x=\frac{16*107.000.000}{10} \\\\ x=16*10.700.000 \\\\ \boxed{x=171.200.000 \ vehicles}$

5 0

3 years ago

Read 2 more answers