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stepan [7]
2 years ago
13

Given the following information, choose the brand that is the better buy.

Mathematics
2 answers:
Lady_Fox [76]2 years ago
6 0
<span>The best buy would be Brand D, because you get more for the money you spend. $1.84 for 16 oz of product comes to .115 cents per ounce which is the cheapers per ounce price of the 4 brands.</span>
BaLLatris [955]2 years ago
3 0

Answer:

d

Step-by-step explanation:

D is correct

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34 inches have the same length of 0.0008636 kilometers.

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2 years ago
Are they right??? <br><br> Due tomorrow
DedPeter [7]
Yes they are right you did a great job!
8 0
3 years ago
The lowest tempature reached on a cold night was -6 degrees Fahrenheit the next day had a high of 15 degrees Fahrenheit what was
Stella [2.4K]
The number is no longer negative and changed in warm ness
7 0
3 years ago
What’s are the answers for both?
nevsk [136]

Answer:

<h2>d = 8</h2><h2>g = 2</h2>

Step-by-step explanation:

8d + 4 = 5d + 28

Group like terms

That's

8d - 5d = 28 - 4

3d = 24

Divide both sides by 3

d = 8

\frac{7(7g + 8)}{4}  = 38.5

Cross multiply

we have

7(7g + 8) = 38.5(4)

49g + 56 = 154

49g = 154 - 56

49g = 98

Divide both sides by 49

g = 2

Hope this helps you

5 0
3 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
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