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iVinArrow [24]
3 years ago
11

A six feet-tall person is standing next to a flag pole.The person is casting a shadow 1 1/2 feet in length,while the flagpoleis

casting a shadow5 feet in length.How tallis the flag pole

Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer:

20 feet

Step-by-step explanation:

Consider the given pictorial representation below,

The Height of the Pole =|AB|

The Height of the Person =|DE|

Shadow cast by the Pole =|AC|

Shadow cast by the Person =|EC|

Triangles ABC and DEC are similar triangles therefore,

\frac{|DE|}{|AB|} =\frac{|EC|}{|AC|}

\frac{6}{x} =\frac{1.5}{5}

Cross multiplying

x X 1.5 = 6 X 5

x=30/1.5 =20 feet

Height of the flag pole = 20 feet

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Use the quadratic formula to find the solution to the question <br> 3x^2-10x+5=0
nlexa [21]

Answer:

x_{1}  = \frac{5 + \sqrt{10} }{3}  and x_{2} = \frac{5 - \sqrt{10} }{3}

Step-by-step explanation:

3x^2-10x+5=0

x_{1} = \frac{10 + \sqrt{10^{2}-4*3*5 } }{2*3}                  x_{2} = \frac{10 - \sqrt{10^{2}-4*3*5 } }{2*3}

x_{1} = \frac{10 + \sqrt{100-60} }{6}                      x_{2} = \frac{10 - \sqrt{100-60} }{6}

x_{1} = \frac{10 + \sqrt{40} }{6}                            x_{2} = \frac{10 - \sqrt{40} }{6}

x_{1} = \frac{10 + 2\sqrt{10} }{6}  / 2                    x_{2} = \frac{10 - 2\sqrt{10} }{6}  / 2

x_{1}  = \frac{5 + \sqrt{10} }{3}                             x_{2} = \frac{5 - \sqrt{10} }{3}

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