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Basile [38]
3 years ago
12

A line through the origin has a slope of 1 / 3. Carlos thinks the slope of a perpendicular line at the origin will be 3.

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

Carlos is incorrect.

Step-by-step explanation:

We have been given that a line through the origin has a slope of \frac{1}{3}. Carlos thinks the slope of a perpendicular line at the origin will be 3.

We know that the slope of a perpendicular line to a given line is always negative reciprocal of the slope of the given line.

The slope of the perpendicular line at the origin will be negative reciprocal of \frac{1}{3}.

Let us find negative reciprocal of \frac{1}{3} as:

-\frac{1}{\frac{1}{3}}=-\frac{1\cdot 3}{1}=-3

Since the slope of a perpendicular line at the origin is -3, therefore, Carlos is incorrect.

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A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590
Jet001 [13]

Let's assume

height of plane  in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

y-y_1=m(x-x_1)

points as

(5,6500)

x1=5, y1=6500

(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug values

m=\frac{5900-6500}{7-5}

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Equation of line:

we can use formula

y-y_1=m(x-x_1)

we can plug values

h-6500=-300(t-5)

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Time of landing:

we can set h=0

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