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anastassius [24]
3 years ago
14

A constant force is applied to a body that is already moving. The force is directed at an angle of 60 degrees to the direction o

f the body's velocity. What is most likely to happen is that: the body will stop moving. the body will move in the direction of the force. the body's velocity will increase in magnitude but not change direction. the body will gradually change direction more and more toward that of the force while speeding up. the body will first stop moving and then move in the direction of the force.
Physics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

the body will gradually change direction more and more toward that of the force while speeding up.

Explanation:

From the question we were told that constant force is applied to a body that is already moving

if the applied force is in opposite direction to the motion of the object, there would be deceleration.

Whenever a force is applied to moving body , acceleration will occur in the body if the force and the motion of the body act in the same direction.

However in case of the question since the force is directed at an angle of 60 degrees to the direction of the body's velocity then the body will gradually change direction more and more toward that of the force while speeding up.

.

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a wave travels in a string at 58 m/s. a second string of 10% greater linear density has the same tension applied as in the first
ozzi

Answer:

The speed of wave in the second string is 55.3 m/s.

Explanation:

Given that,

Speed of wave in first string= 58 m/s

We need to calculate the wave speed

Using formula of speed for first string

v_{1}=\sqrt{\dfrac{T}{\mu_{1}}}...(I)

For second string

v_{2}=\sqrt{\dfrac{T}{\mu_{2}}}...(II)

Divided equation (II) by equation (I)

\dfrac{v_{2}}{v_{1}}=\sqrt{\dfrac{\dfrac{T}{\mu_{2}}}{\dfrac{T}{\mu_{1}}}}

Here, Tension is same in both string

So,

\dfrac{v_{2}}{v_{1}}=\sqrt{\dfrac{\mu_{1}}{\mu_{2}}}

The linear density of the second string

\mu_{2}=\mu_{1}+\dfrac{10}{100}\mu_{1}

\mu_{2}=\dfrac{110}{100}\mu_{1}

\mu_{2}=1.1\mu_{1}

Now, Put the value of linear density of second string

\dfrac{v_{2}}{v_{1}}=\sqrt{\dfrac{\mu_{1}}{1.1\mu_{1}}}

v_{2}=v_{1}\times\sqrt{\dfrac{1}{1.1}}

v_{2}=58\times\sqrt{\dfrac{1}{1.1}}

v_{2}=55.3\ m/s

Hence, The speed of wave in the second string is 55.3 m/s.

5 0
4 years ago
Flammability is an example of a _________ property.
dsp73
Flammability is an example of a chemical property
5 0
4 years ago
Read 2 more answers
What is the frequency of a wave moving at 1782 m/s if its wavelength is 30.2 m?
Inessa [10]

Answer:

Explanation:

Wavelength = Velocity / Frequency

= 1782/30.2

= 59 metre.

4 0
3 years ago
a car traveling at 28 m/s slows down at a constant rate for 4 seconds until it stops. what is its acceleration?
astra-53 [7]
We are given the following conditions:
v_{0} = 28m/s

t = 4s

v_{f} = 0m/s

Since we are told it slows down at a constant rate, we know we are dealing with uniformed accelerated motion, or UAM for short.

So we look at our kinematics equation that contains the given variables.

v_f = v_0 + at

This contains our target variable and our initial conditions. Plug and chug, we get:

(0m/s) = (28m/s) + a(4s) -28m/s = (4s)*a a = -7m/s^2

Thus the answer is:

a = -7m/s^2

Hope this helps!


3 0
4 years ago
An object has a mass of 450g. What is the gravitational force of the object by earth?
anygoal [31]

Answer:

4.41N or 4.5N (check explanation)

Explanation:

450g = 0.45kg

F = ma

Using 10m/s² = 10(0.45) = 4.5N

Using 9.8m/s² = 9.8(0.45) = 4.41N

5 0
3 years ago
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