Answer:
The speed of wave in the second string is 55.3 m/s.
Explanation:
Given that,
Speed of wave in first string= 58 m/s
We need to calculate the wave speed
Using formula of speed for first string
...(I)
For second string
...(II)
Divided equation (II) by equation (I)

Here, Tension is same in both string
So,

The linear density of the second string



Now, Put the value of linear density of second string




Hence, The speed of wave in the second string is 55.3 m/s.
Flammability is an example of a chemical property
Answer:
Explanation:
Wavelength = Velocity / Frequency
= 1782/30.2
= 59 metre.
We are given the following conditions:

Since we are told it slows down at a constant rate, we know we are dealing with uniformed accelerated motion, or UAM for short.
So we look at our kinematics equation that contains the given variables.

This contains our target variable and our initial conditions. Plug and chug, we get:

Thus the answer is:
a = -7m/s^2
Hope this helps!
Answer:
4.41N or 4.5N (check explanation)
Explanation:
450g = 0.45kg
F = ma
Using 10m/s² = 10(0.45) = 4.5N
Using 9.8m/s² = 9.8(0.45) = 4.41N