4 years ago

Flammability is an example of a _________ property.

Physics

2 answers:

vovikov84 [41]4 years ago

6 0

Chemical property is the answer

dsp734 years ago

5 0

Flammability is an example of a chemical property

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an athlete running 2.6m/ increases his velocity to 3.7m/s in 2.7s. what is the acceleration of the runner

iVinArrow [24]

Acceleration= velocity/time

1.1/2.7=0.41

The acceleration is .41 m/s^2

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3 years ago

Now open the simulation. Activate ""grid"" and ""show numbers"" to read values. Place a 1 nC positive (red color) charge on the

zmey [24]

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The divergence on the sensor shows the magnitude of the charges

Explanation:

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3 years ago

What is a way to make magnets? <br><br> Heating<br> Pressure<br> Freezing

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The horizontal surface on which the 2.0 - kg block slides is frictionless. The speed of the block before it touches the spring i

vlabodo [156]

Answer:

0.918 seconds

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M = 2kg

V = 9.0 m/s

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F = Mg cosΘ

Θ = 0°

But F = Ma

a = v / t

F = m*v / t

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3 years ago

A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma

tresset_1 [31]

Answer:

Explanation:

a. Given that:

$m-$ mass of first & second piece, $3m-$ mass of 3rd piece, $\bar v_1$ -velocity of first piece( $-23\dot i \ m/s$ ) and $\bar v_2$ as velocity of 2nd piece ( $-23\dot j \ m/s$ )

Let $\bar v_3$ be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

$m\bar v_1 +m\bar v_2 +3m \bar v_3=0$ #Dividing both sides by $m, m\neq 0$

$\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)$

#Plug the $\bar v_1 ,\bar v_2$ values:

$\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)$

#So the magnitude of the third piece is:

$|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s$

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the $x$ -axis), we find $\angle \theta$ . The angle is obtained by getting the tan inverse as:

$\theta=tan^-^1(\frac{23/3}{23/3})\\=45\textdegree$

-The direction of the magnitude (angle relative to the x-axis) is 45°

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3 years ago