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soldier1979 [14.2K]
3 years ago
5

The ______ length of a lens is the distance from the center of the lens to its principal focus.

Physics
1 answer:
Marizza181 [45]3 years ago
3 0

Answer:

<h2>Focal length</h2>

Explanation:

The Focal length of a lens is the distance from the center of the lens to

its principal focus.

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Answer: the answer is true :-)

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a horse stands on a flat surface if the horse has a mass of 186 kg what is the normal force acting on it
astra-53 [7]
The mass of the horse is 186 kg.

The weight of the horse is
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3 years ago
Please help me with questions 1, 2 and 3. <br> i need a step by step explanation
kifflom [539]

Answer:

1) d

2) 5 m/s

3) 100

Explanation:

The equation of position x for a constant acceleration a and an initial velocity v₀, initial position x₀, time t is:

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The equation for velocity v and a constant acceleration a is:

(ii) v=at+v_0

1) Solve equation (ii) for acceleration a and plug the result in equation (i)

(iii) a = \frac{v -v_0}{t}

(iv) x = \frac{v-v_0}{2t}t^2+v_0t + x_0

Simplify equation (iv) and use the given values v = 0, x₀ = 0:

(v) x=-\frac{v_0}{2}t + v_0t= \frac{v_0}{2}t

2) Given v₀= 3m/s, a=0.2m/s², t=10 s. Using equation (ii) to get the final velocity v:v=at+v_0=0.2\frac{m}{s^2} * 10s+3\frac{m}{s}=2\frac{m}{s}+3\frac{m}{s}=5\frac{m}{s}

3) Given v₀=0m/s, t₁=10s, t₂=1s and x₀=0. Looking for factor f = x(t₁)/x(t₂) using equation(i) to calculate x(t₁) and x(t₂):

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5 0
3 years ago
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