Because these are not like terms, they cannot be combined. The variables are different, that's what makes them not like terms
Answer:
The length of the actual building is 112 meters long.
Step-by-step explanation:
The key words we need to know are these : scale is 1 millimeter = 7 meters, and 16 millimeters long.
The question is asking for the building's actual height.
To solve this, we need to set up a ratio, have the scale being one ratio and the other 16 millimeters over blank. It's going to look like this :
= 
We need to make sure all the units are lined up - the mm parts of the ratio are next to each other.
Now that we have our ratio set up we can cross product to solve for x.
1(x) = 16(7)
x = 112
So x is 112, or the length of the actual building is 112 meters long.
Hope this helps, please mark brainliest if possible. Have a nice day. :)
Answer:
![= \left[\begin{array}{c}1500&1225&1200\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1500%261225%261200%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given



Required
Represent as a matrix
For Sammy:

So, we have:


For Jamie:

So, we have:


For Yvonne:

So, we have:


The system of equations are:



To represent as a matrix, we have:
![= \left[\begin{array}{c}Total_1&Total_2&Total_3\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7DTotal_1%26Total_2%26Total_3%5Cend%7Barray%7D%5Cright%5D)
This gives:
![= \left[\begin{array}{c}1500&1225&1200\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1500%261225%261200%5Cend%7Barray%7D%5Cright%5D)
what is the height of it
and what do you want me to find?