The answer is -1/4 I’m in 11th grade trust me
Answer:
hola quetall cm eatanfufuguvuggugdyfyxjcjv
9514 1404 393
Answer:
(-3, 3)
Step-by-step explanation:
The blanks are trying to lead you through the process of finding the point of interest.
__
The horizontal distance from T to S is <u> 9 </u>. (or -9, if you prefer)
The ratio you're trying to divide the line into is the ratio that goes in this blank:
Multiply the horizontal distance by <u> 2/3 </u>. (9×2/3 = 6)
Move <u> 6 </u> units <u> left </u> from point T.
The vertical distance from T to S is <u> 6 </u>.
Multiply the vertical distance by <u> 2/3 </u>. (6×2/3 = 4)
Move <u> 4 </u> units <u> up </u> from point T.
__
Point T is (3, -1) so 6 left and 4 up is (3, -1) +(-6, 4) = (3-6, -1+4) = (-3, 3). The point that is 2/3 of the way from T to S is (-3, 3).
1/6p + (-4/5) is the equivalent expression. You have to add like terms, meaning constants are added to constants, variables are added to variables, etc. the result you get from adding like variables leaves you with 1/6p + (-4/5) or 1/6p - 4/5
Answer:
1c
![n = 33](https://tex.z-dn.net/?f=n%20%3D%2033)
1d
![n = 19](https://tex.z-dn.net/?f=n%20%3D%2019)
Step-by-step explanation:
From the question we are told that
The probability of telesales representative making a sale on a customer call is ![p = 0.15](https://tex.z-dn.net/?f=p%20%3D%200.15)
The mean is ![\mu = 5](https://tex.z-dn.net/?f=%5Cmu%20%20%3D%20%205)
Generally the distribution of sales call made by a telesales representative follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the mean is mathematically represented as
![\mu = n* p](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%20n%2A%20%20p)
=> ![5= n * 0.15](https://tex.z-dn.net/?f=5%3D%20n%20%2A%20%200.15)
=> ![n = 33](https://tex.z-dn.net/?f=n%20%3D%2033)
Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as
![P( X \ge 1) = 1 - P( X < 1 ) > 0.95](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%201%29%20%3D%201%20-%20P%28%20X%20%3C%201%20%29%20%3E%200.95)
=> ![P( X \ge 1) = 1 - P( X =0 ) > 0.95](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%201%29%20%3D%201%20-%20P%28%20X%20%3D0%20%29%20%3E%200.95)
=> ![P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%201%29%20%3D%201%20-%20%5B%20%5E%7Bn%7DC_0%20%2A%20%20%280.15%20%29%5E0%20%2A%20%20%281-%200.15%29%5E%7Bn-0%7D%5D%20%3E%200.95)
=> ![1 - [1 * 1* (0.85)^{n}] > 0.95](https://tex.z-dn.net/?f=%201%20-%20%5B1%20%20%2A%20%201%2A%20%20%280.85%29%5E%7Bn%7D%5D%20%3E%200.95)
=> ![[(0.85)^{n}] > 0.05](https://tex.z-dn.net/?f=%20%20%5B%280.85%29%5E%7Bn%7D%5D%20%3E%200.05)
taking natural log of both sides
![n = \frac{ln(0.05)}{ln(0.85)}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Bln%280.05%29%7D%7Bln%280.85%29%7D)
=> ![n = 19](https://tex.z-dn.net/?f=n%20%3D%2019)