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kupik [55]
4 years ago
7

Solve the system of equations below by graphing both equations with a pencil and paper. What is the solution? y = x + 5 y = –2x

– 1 A. (0, –1) B. (0, 5) C. (–2, 3) D. (–2, –1)

Mathematics
2 answers:
ipn [44]4 years ago
7 0
Look at the picture. Here I have inserted the two functions, the green is the first. Can you find the solution? I also included all the answers.

masha68 [24]4 years ago
6 0

Answer:

C. (–2, 3)

Step-by-step explanation:

Given :

y=x+5\\y=-2x-1

Solution :

Equation a : y=x+5

Equation b : y = -2x-1

We will use substitution method

Putting the value of y from equation a in equation b

⇒x+5 = -2x-1

⇒x+2x= -1-5

⇒3x= -6

⇒x=\frac{-6}{3}

⇒x=-2

Now substituting value of x in equation a to get value of y

⇒y=x+5

⇒y=-2+5

⇒y=3

Thus the solution of given system of equations is (-2,3)

Thus The Option C is correct.

We have also solved it by graphing the equations you can refer the attached figure.


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Answer:

a. A plot of berkeley vs time and berkeley vs stbarb can be found in the 1st and 2nd image attachments

b. A plot of the residual diagnostics regression of berkeley on time can be found in the 3rd image attachment

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d. A plot of the variable berkeley and an ACF plot of the data can be found as the first diagram in the fifth image attachment. The time series here has an increasing trend which means that it could not possibly be stationary. The ACF plot is difficult to interpret since the data is not stationary. It cannot be interpreted as an approximation to the auto-correlation function.

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The data here seems to be fairly stationary after differencing with a fairly constant variance and no discernible trend.

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Step-by-step explanation:

I have attached images of this solution to represent the various constraints plotted against each other.

a. The plots of berkeley vs time and berkeley vs stbarb are contained in the first and second image attachments.

b. The residual diagnostics plots of a regression of berkeley on time(including the ACF) are contained in the third image attachment.

Inferences can be made thus:

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Adjusted R-Squared: 0.3956

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