Given:
A regular polygon with three vertices and side 14 cm.
To find:
Area of the regular polygon.
Solution:
We know that, a regular polygon has equal sides and equal interior angles.
The given regular polygon has three equal sides, it means it is an equilateral triangle.
The area of an equilateral triangle is:
Where, a is the side length of the triangle.
Putting , we get
Therefore, the area of given regular polygon is 84.9 cm².
Answer:
f(x) = 0.5x + 2
f(x) = 1/2x + 2
y - 3 = 1/2(x - 2)
y - 1 = 0.5(x + 2)
Step-by-step explanation:
In the figure attached, the graphed line is shown.
The missing options are:
<em>f(x) = 0.2x - 4 </em>
<em>f(x) = 0.5x + 2 </em>
<em> f(x) = 1/2x + 2 </em>
<em> y – 3 = 1/2(x – 2) </em>
<em> y – 1 = 0.5(x + 2)</em>
From the picture, we can see that points (0, 2) and (2, 3) are on the line. Then, the slope of the line is:
m = (3 - 2)/(2 - 0) = 1/2 = 0.5
The y-intercept is (0, 2), or b = 2
Therefore, in the slope y-intercept form, the equation is:
f(x) = mx + b
f(x) = 1/2x + 2 = 0.5x + 2
In the point-slope form, the equations is:
y - y1 = m(x - x1)
y - 3 = 1/2(x - 2)
Using point (-2, 1), in the point-slope form, the equation is:
y - y1 = m(x - x1)
y - 1 = 0.5(x + 2)
