Replace ? with =, >, or < to make the statement true.

Marcela is registering for her college classes, which cost $105 per unit. How many units can she take to have a maximum cost of

OverLord2011 [107]

Answer:

Marcela can take up to 13 units.

Step-by-step explanation:

In order to find the number of units that Marcela can take for her college classes, we can set up an inequality and solve for the variable. Since each unit costs $105, we can say that 105u ≤ 1365 where u = the number of units. The number of units multiplied by the cost per unit, must be less than or equal to $1,365. In order to solve for 'u', we can use inverse (opposite) operations and get rid of the coefficient by dividing both sides of the inequality by 105. 1365÷105 = 13. So, the number of units that Marcela can take must be less than or equal to 13 units.

6 0

3 years ago

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Suppose x and y vary together such that x is 7 times as large as y. write a formula that defines x in terms of y.

Ainat [17]

Since y is less than x by 7 times $\frac{x}{7}=y$ so in terms of x we write
x=7y

4 0

3 years ago

Find the value of x if 7,x and 11 are in A.p.

krok68 [10]

Answer:

x = 9

Step-by-step explanation:

since the terms are in AP then there is a common difference between consecutive terms, that is

a₂ - a₁ = a₃ - a₂ ( substitute values )

x - 7 = 11 - x ( add x to both sides )

2x - 7 = 11 ( add 7 to both sides )

2x = 18 ( divide both sides by 2 )

x = 9

7 0

2 years ago

Read 2 more answers

Type SSS, SAS, ASA, SAA, or HL to<br> describe these triangles.

Yanka [14]

Answer:

SSS

Both these triangles are congruent to each other by SSS congruency

Hope it helps

7 0

3 years ago

Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b

Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A = (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

$Slope, m \, of \. base, \, AC= \frac{dy}{dx} = \frac{b - b}{a - (-a)} = \frac{0}{2\cdot a} = 0$

Hence, segment AC is vertical

$Slope, m \, of \, segment \ CP \, joining \, vertex, \, to \, midpoint, P, on \,AC = \frac{0 - b}{0 - 0} = \frac{-b}{0} = Undifined.$

Hence, segment CP is vertical

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.

6 0

3 years ago