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erma4kov [3.2K]
3 years ago
6

[Ignore the 2 problems] I need help on #9

Mathematics
1 answer:
3241004551 [841]3 years ago
6 0
A.) x (5 + x) = 5x + x^2
B.) 2 (5 + x) = 10 + 2x
You might be interested in
What is the soluition ​
Juli2301 [7.4K]

Answer:

b > 3 2/15.

Step-by-step explanation:

2 3/5  < b - 8/15

b > 2 3/5 + 8/15

b > 13/5 + 8 / 15

b > 39/15 + 8/15

b >  47/15

b > 3 2/15.

5 0
3 years ago
An item is regularly priced at $51. Amanda bought it on sale for 85% off the regular price. How much did Amanda pay?
siniylev [52]

Answer:

85% off $51 is $43.35 which equals to $7.65

Amanda paid only $7.65 for the 85% off the original price.

Step-by-step explanation:

4 0
3 years ago
Rhonda drove 51 miles per hour for 5 hours. She then drove 55 miles per hour for x hours. Which expression is equivalent to the
lawyer [7]

The expression equivalent to the total distance Rhonda drove is 51x = 275

Given:

Distance 1:

Number of miles = 51 miles

Number of hours = 5 hours

Distance 2:

Number of miles = 55 miles

Number of hours = x hours

<em>Ratio of miles to number of hours</em> = 51 miles : 5 hours

<em>Ratio of miles to number of hours</em> = 55 miles : x hours

Equate the ratios

51 : 5 = 55 : x

51/5 = 55/x

cross product

51 × x = 5 × 55

51x = 275

x = 275 / 51

x = 5.392156862745098

Approximately,

x = 5.4 hours

Therefore, the number of hours taken to travel 55 miles is 5.4 hours

Read more:

brainly.com/question/3796978

7 0
3 years ago
5 bullets in a 6 bullet barrell, what are your chances of dying on the first trigger pull?​
Ostrovityanka [42]
Ehh considering i’ve thought about it before, i’d say abt 83 to 85 percent chances of me dying
6 0
2 years ago
Read 2 more answers
a major metroplitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers. they aske
Arisa [49]

Answer:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1600, \pi = 0.4

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.3685

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.4315

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

7 0
2 years ago
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