Y^2+4y=-8
add 8 both sides
y^2+4y+8=0 in the form of ax²+bx+c=0
Factor it
by formula
-b+-(√b²-4ac)/2a
-4+-(√16-32)/2*1
-4+-(√-16)/2
-4+-4i/2
-2+-2i where√-1=i
To calculate the remaining number of teams, use the sequence formula:
a(n) = a(1)Rⁿ-¹
Where a(n) and a(1) are the nth and first terms. R is the factor. Therefore, 24 teams is valid value.
After 5 rounds :
a(5) = 128*(½)⁴
a(5) = 128/16 = 8
8 teams are remained.
Let the boy be B and the girl be G
there are six possible outcomes
BGG, GBB, GBG, BGB, BBB, and GGG
therefore the probability of getting one boy and two girls is
also the probability of getting 3 girls is
Answer: G
Step-by-step explanation: the rate of change is constant, making it a proportional relationship
C. To find the y-intercept, substitute in 0 for x and solve for y. y-intercept= (0,33)