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VladimirAG [237]
3 years ago
11

How to calculate a probability

Mathematics
1 answer:
Lelu [443]3 years ago
6 0
Probability is calculated by comparing the odds to a certain event occurring to the number of possible events.

P=\frac{possibility-of-an-event-occuring}{number-of-total-outcomes}

For example, take a six-sided dice number 1-6 on each side. The probability of rolling a 4 would be1 in 6 or 1/6. This is because of the six possible outcomes, rolling a 4 is only one of them.

P(4)=1/6

Now take the same dice. The probability of rolling an even number is 3/6. To see why, lets look at the total possible outcomes:

1
2
3
4
5
6

Of the 6 possibilities, 3 are even numbers.

P(even)=3/6 or 1/2
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A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged
Alexxx [7]

Answer:

a) E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

b) First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

c) P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

d) P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

X \sim Unif (a= 100,  b=1100)

Part a

For this case the average is given by the expected value and we can use the following formula:

E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

Part b

First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100

And we can find this probability:

P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

Part d

P(311 < X< 889) = P(X

And using the cdf we got:

P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

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6(b+1)=8<br> Solve for x
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Answer:

b = 1/3

Step-by-step explanation:

6(b+1)=8

Solving for b

Distribute

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6b = 2

Divide by 6

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