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o-na [289]
3 years ago
8

Explain about herb some lines​

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

Herbs are small plants that have a fleshy or juicy stem when they are young. The stems of some herbs develop hard, woody tissue when they grow old. Most herbs are perennials. This means that the tops of the plants die each growing season, but the roots remain alive and produce new plants year after year.

Step-by-step explanation:

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How do you solve 37.35= 15/x
Serjik [45]

Answer:

see below

Step-by-step explanation:

multiply both sides by x

37.35 = \frac{15}{x}

x * 37.35 = \frac{15}{x} *x

the x on the right side cancel out

37.35x = 15

now divide both sides by 37.35

\frac{37.35x}{37.35} = \frac{15}{37.35}

x = \frac{15}{37.35}

x ≈ 0.402

8 0
4 years ago
Abram competed in a 100-meter swimming race. He swam
uysha [10]

Answer:

Step-by-step explanation:

59.89

3 0
3 years ago
In a music competition, a participant has to score a total of at least 40 points in the first four rounds combined to move on to
lisov135 [29]

Answer:

4p+3≥40

Step-by-step explanation:

8 0
3 years ago
A radioactive substance decays at a continuous rate of 17% per year, and 250 mg of the substance is present in the year 2009.
yaroslaw [1]

Answer:

a) A(t) = 250 (1-0.17)^t = 250(0.83)^t

b) A(t=14) = 250 (0.83)^{14}= 18.408 mg

c) For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

Step-by-step explanation:

Part a

For this case we know that the decay rate per year is about 17% or 0.17 in fraction and the initial amount is 250 mg for 2009, we can define the model like this:

A(t) = A_o (1-r)^t

Where A represent the amount of the substance in mg, r the decay rate = 0.17 and t the number of years after 2009.

Our model for this case would be:

A(t) = 250 (1-0.17)^t = 250(0.83)^t

Part b

For this case we have that t= 2023-2009=14 years, so then we can find the amount of substance like this:

A(t=14) = 250 (0.83)^{14}= 18.408 mg

Part c

For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

6 0
3 years ago
You deposit $2,500 in a special savings account. The account earns interest at a rate of 3.25% compounded monthly. a. What amoun
fgiga [73]

Answer:

1. $2906.25

2. $406.25

Step-by-step explanation:

2500+ (3.25% of 2500) (5)

2500+ (81.25) (5)

2500+ $406.25

=2906.25

3.25% of 2500

=406.25

5 0
3 years ago
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