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leonid [27]
3 years ago
7

The diagram shows the dimensions of Mr. Green's garden. A bag of fertilizer costs $3 and covers an area of about 50 square feet.

What will be the cost for Mr. Green to fertilize his garden?​

Mathematics
2 answers:
julia-pushkina [17]3 years ago
8 0

Answer:

The area of his garden is  

✔ 84  ft

2.  Mr. Green will need  

✔ 2  bags of fertilizer.

The cost will be $

✔ 6

Komok [63]3 years ago
4 0

Answer:

just multiply the numbers

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A recipe has a ratio of 1 1/2 cups of cheese to 6 oz. of pasta. Based on this recipe, which statement is true?
yarga [219]

The ratio is 1 1/2 cups of cheese to 6 oz of pasta. All statements have 1 cup of cheese, so let's find the corresponding amount of pasta using a rule of three:

\begin{gathered} 1\frac{1}{2}\text{ cups cheese}\to6\text{ oz pasta} \\ 1\text{ cup cheese}\to x\text{ oz pasta} \\  \\ \frac{1\frac{1}{2}}{1}=\frac{6}{x} \\ \frac{3}{2}=\frac{6}{x} \\ 3x=12 \\ x=4 \end{gathered}

So the amount of pasta is 4 oz, therefore the correct statement is B.

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1 year ago
a car rental company charges $34 per day for a rented car and $0.50 for every mile driven. A second car rental company charges $
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Answer:

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Step-by-step explanation:

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Anna [14]

Answer:

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Step-by-step explanation:

The number of tips that the server gets is <em>dependent</em> on how many customers she serves.

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3 years ago
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Sandrena and her friends brought frozen yogurt for 55 cents per ounce.their total was $10.45.how many ounces did they buy?
lianna [129]
You would divide 10.45 by .55 and you would get 19 so 19 is your answer hope this helps
6 0
4 years ago
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
3 years ago
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